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klemol [59]
3 years ago
11

Lisa has a rope that measures 9 1 4 feet in length. She will cut the rope into pieces that are each 3 4 foot long. How many full

pieces can Lisa cut from her rope, and how much of her rope will be remaining?
Mathematics
2 answers:
Harman [31]3 years ago
3 0

Answer:

Lisa can cut the rope into 12 pieces with 1/4 foot remaining.

I found the answer on USATestprep.

sammy [17]3 years ago
3 0

Answer:

B)

Step-by-step explanation:

Hope this helped!

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5y(4y^2−2y)+3y(−2y^2+4y)<br><br>Please help
Alona [7]

Answer:

factor the expression =2y^2 (7y+1) or simplify it=14y^3 + 2y^2

Step-by-step explanation:

5 0
3 years ago
How do you round 2.8497 × 10^3 and 349.69 to 3 significant figures?
Kobotan [32]

Your answer for rounding 2.8497 x 10^3 is correct: 2.85 x 10^3.

350.0 is not correct because it has 4 sig figs. The proper rounding would be simply 350. with not additional zeros.

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There are 36 pencils in 6 packs. Igor wants to know how many pencils are in 1 pack. Elsa wants to know how many pencils are in 3
enyata [817]
Igor: 6 pencils: 1 pack
Elsa: 18 pencils: 3 packs
6 0
3 years ago
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For the following hypothesis test, determine the null and alternative hypotheses. Also, classify the hypothesis test as two-tail
bagirrra123 [75]

Answer:

Option B:

H_0: \mu = 22.1

H_a: \mu \neq 22.1

Classification:

The hypothesis test is Two-tailed.

Step-by-step explanation:

The mean length of imprisonment for motor-vehicle theft offenders in this country is 22.1 months.

This means that the null hypothesis is that the mean is of 22.1 months, that is:

H_0: \mu = 22.1

A hypothesis test is to be performed to determine whether the mean length of imprisonment for motor-vehicle theft offenders in this city differs from the national mean of 22.1 months.

At the alternate hypothesis, we test if this mean is different of 22.1, that is:

H_a: \mu \neq 22.1

Which means that the answer is given by option b).

Which of the following is the correct classification of the hypothesis test?

We test if the mean is different from a value, which means that the hypothesis test is Two-tailed.

7 0
3 years ago
Which expression is equivalent to the following complex fraction? StartFraction 1 Over x EndFraction minus StartFraction 1 Over
Darina [25.2K]

Answer:

\frac{y-x}{x+y}

Step-by-step explanation:

We are given that fraction

\frac{\frac{1}{x}-\frac{1}{y}}{\frac{1}{x}+\frac{1}{y}}

We have to find the expression which is equivalent to given  fraction .

\frac{1}{x}-\frac{1}{y}=\frac{y-x}{xy}

\frac{1}{x}+\frac{1}{y}=\frac{x+y}{xy}

Substitute the values  then, we get

\frac{\frac{y-x}{xy}}{\frac{y+x}{xy}}

We know that

\frac{\frac{a}{b}}{\frac{x}{y}}=\frac{a}{b}\times \frac{y}{x}

Using the property then, we get

\frac{y-x}{xy}\times \frac{xy}{x+y}

\frac{y-x}{x+y}

This is required expression which is equivalent to given expression.

6 0
3 years ago
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