Jacob wants to build a rectangular enclosure for his animals. One side of the pen will be against the barn,so he needs no fence on that side.
Let w be the width of the enclosure (perpendicular to the barn) and let l be the length of the enclosure (parallel to the barn).
one side of the length is not counted for perimeter because one side of length will be against the barn.
Perimeter = 400 ft
Perimeter of rectangle = L + W + W
400 = L + 2W
L = 400 - 2W
Area = L * W
Replace L by 400 - 2W
A(W) = (400 - 2W) * W
Now we find out x coordinate of vertex to find the width that maximize the area
a= -2 and b = 400
The width w would maximize the area is w = 100ft
To find maximum area we plug in 100 for W in A(W)
the maximum area is 20,000 square feet
Ok...so u have 4 people sharing this plan...they each pay for their own data..however, the $ 90 flat rate is split between them equally.
90/4 = 22.5....so each of them pay 22.50 each for the flat rate.
so John's equation is : 22.5 + 0.25x = 147.50
Answer:
Part A: 7n + 30= -5 and 8n + 40= 16
Part B: 7(8) + 30= 86 and 8(8) + 40= 104
Part C: Company A saves you 12.
Step-by-step explanation:
Company A: 7n + 30
Company B: 8n + 40
7n + 30= -5 8n + 40= 16
7(8) +30= 86 8(8) +40= 104
7(2) + 30= 44 8(2) + 40= 56
56 - 44= 12
Answer:No Matt's calculation is not correct.
Step-by-step explanation:
We have to multiply by the number of the area.If it is 4 inches we multiply by 4
15 x 4 =60
A=4 inches squared
A=LxW (length x width )
so you can say that:
Matt is incorrect because He skipped the step of multiplying 2 by 2 in the formula which is where we get 4 from.
The answer is d as in dog
