Answer:
Explanation:
Weight of NaCl is equal to sum of weight of one mole of sodium and one mole of chloride.
Mathematically, it can be represented as -
1 mol (Na) 
1 mol (Cl) 
g/mol
In 
gram of NaCl, there is one mole of Na or 
ions
In one gram of NaCl, there will be
sodium ions
In 
grams of NaCl, the number of sodium ions will be -
Answer:
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Explanation:
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High concentration of water and salt is the main ingredient of brine. Salt being NaCl and water make brain and important solution in making of chlorine.
Electric terminals are put inside the solutions and with the help of electric current the chemical properties of the solution are changed such that we get chlorine as outcome. This process is carried out in a large scale to get chlorine from NaCl in solution and is called electrolysis of Brine.
The idea here is that you need to figure out how many moles of magnesium chloride,
MgCl
2
, you need to have in the target solution, then use this value to determine what volume of the stock solution would contain this many moles.
As you know, molarity is defined as the number of moles of solute, which in your case is magnesium chloride, divided by liters of solution.
c
=
n
V
So, how many moles of magnesium chloride must be present in the target solution?
c
=
n
V
⇒
n
=
c
⋅
V
n
=
0.158 M
⋅
250.0
⋅
10
−
3
L
=
0.0395 moles MgCl
2
Now determine what volume of the target solution would contain this many moles of magnesium chloride
c
=
n
V
⇒
V
=
n
c
V
=
0.0395
moles
3.15
moles
L
=
0.01254 L
Rounded to three sig figs and expressed in mililiters, the volume will be
V
=
12.5 mL
So, to prepare your target solution, use a
12.5-mL
sample of the stock solution and add enough water to make the volume of the total solution equal to
250.0 mL
.
This is equivalent to diluting the
12.5-mL
sample of the stock solution by a dilution factor of
20
.
8 because atomic number is the same as number of protons, protons and electrons have the same amount so that the element is neither positive nor negative.
