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alexdok [17]
3 years ago
6

Identify the oxidized substance, the reduced substance, the oxidizing agent, and the reducing agent in the redox reaction. Cu(s)

+2AgNO3(aq)⟶2Ag(s)+Cu(NO3)2(aq)
Chemistry
1 answer:
spin [16.1K]3 years ago
4 0

<u>Answer:</u> Copper is getting oxidized and is a reducing agent. Silver is getting reduced and is oxidizing agent.

<u>Explanation:</u>

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

X\rightarrow X^{n+}+ne^-

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

X^{n+}+ne^-\rightarrow X

Oxidizing agents are defined as the agents which oxidize other substance and itself gets reduced. These agents undergoes reduction reactions.

Reducing agents are defined as the agents which reduces the other substance and itself gets oxidized. These agents undergoes reduction reactions.

For the given chemical reaction:

Cu(s)+2AgNO_3(aq.)\rightarrow 2Ag(s)+Cu(NO_3)_2(aq.)

The half reactions for the above reaction are:

<u>Oxidation half reaction:</u>  Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-

<u>Reduction half reaction:</u>  2Ag^+(aq.)+2e^-\rightarrow 2Ag(s)

From the above reactions, copper is loosing its electrons. Thus, it is getting oxidized and is considered as a reducing agent.

Silver is gaining electrons and thus is getting reduced and is considered as an oxidizing agent.

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Jobisdone [24]

Answer:

\rho=3.1g/mL

Explanation:

Hello,

In this case, considering that the density of a body is computed given its mass and volume:

\rho =\frac{m}{V}

Taking into account that the mass is 24.32 g and the volume is computed via the difference between the volume of the water with the brass and the volume of water by itself as follows:

V=13.50mL-5.60mL=7.9mL

The density of the piece of brass turns out:

\rho =\frac{24.32g}{7.9mL}\\\\\rho=3.1g/mL

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Svet_ta [14]

Answer:

The number of neutrons present in one atom of isotope of Silicon of mass 28 amu is<u> 14 neutrons</u>

Explanation:

Symbol of Si isotope

_{14}^{28}\textrm{Si}

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50.0 mL of an HNO^3 solution were titrated with 36.90 mL of a 0.100 M LiOH solution to reach the equivalence point. What is the
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Answer:

0.0738 M

Explanation:

HNO3 +LiOH = LiNO3 + H2O

Number of moles HNO3 = number of moles LiOH

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