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Mekhanik [1.2K]
2 years ago
14

If 1.6 moles of an ideal gas are at a temperature of 25c and a pressure of 0.91 atm hg, what volume would the gas occupy, in lit

ers?
Chemistry
1 answer:
Fiesta28 [93]2 years ago
8 0
From\ Ideal\ Gas\ Law:\\\\PV=nRT\\\\
P-pressure\\V-volume\\n-number\ of\ moles\\R- universal\ gas\ constant\\T-absolute\ tmeperature\\\\
R=\ 8,3145J/ mol\ K\\P=0,91atm\\
n=1,6moles\\T=25c\\\\
Converting\ units:\\\\
1atm=101,3kPa=101,3*10^3\\
0,91atm=0,91*101,3*10^3=92,183*10^3Pa\\T=25c=273+25=298K\\\\
V=\frac{nRT}{P}=\frac{1,6*8,3145*298}{92183}=0,043m^3=43liters\\\\Answer\ is\ 43\ liters.
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A 49.48-mL sample of an ammonia solution is analyzed by titration with HCl. It took 38.73 mL of 0.0952 M HCl to titrate the ammo
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Answer:

M₂ = 0.0745 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = 0.0952 M

V₁ = 38.73 mL

M₂ = ?

V₂ = 49.48 mL

Using the above formula , the molarity of ammonia , can be calculated as ,

M₁V₁ = M₂V₂  

0.0952 M * 38.73 mL = M₂* 49.48 mL

M₂ = 0.0745 M

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Answer:

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The percent mass is defined as a ratio between the mass of a solute and mass of a solution:

\omega = \frac{m_{solute}}{m_{solution}}\cdot 100\%

Since solution only consists of a solute and solvent, express its mass as:

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x = 0.90 + 0.03x

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0.06 = \frac{x}{30.0 + x}\therefore x = 0.06(30.0 + x)

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