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djyliett [7]
3 years ago
7

What is the theoretical yield of so3 produced by the quantities described in part a?\?

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
8 0
The problem here is incomplete. Luckily, I found a similar problem from another website which is shown in the attached picture. So, the useful information here are the stoichiometric coefficients of the reaction and the initial amount of 7.49 g of S. The solution is as follows:

Molar mass of S = 32.06 g/mol
Molar mass of SO₃ = 80.06 g/mol

Theo yield of SO₃ = (7.49 g S)(1 mol S/32.06 g)(2 mol SO₃/2 mol S)(80.06 g SO₃/mol) = <em>18.7 g SO₃</em>

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A 155g sample of an unknown substance was; heated from 25.0°c to 40°c. In the process, the substance absorbed 2085 J of energy.
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Answer:

0.897 J/g°C

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass (M) of substance = 155g

Initial temperature (T1) = 25.0°C

Final temperature (T2) = 40°C

Change is temperature (ΔT) = T2 – T1 = 40°C – 25.0°C = 15°C

Heat Absorbed (Q) = 2085 J

Specific heat capacity (C) of the substance =?

Step 2:

Determination of the specify heat capacity of the substance.

Applying the equation: Q = MCΔT, the specific heat capacity of the substance can be obtained as follow:

Q = MCΔT

C = Q/MΔT

C = 2085 / (155 x 15)

C = 0.897 J/g°C

Therefore, the specific heat capacity of the substance is 0.897 J/g°C

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