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djyliett [7]
3 years ago
7

What is the theoretical yield of so3 produced by the quantities described in part a?\?

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
8 0
The problem here is incomplete. Luckily, I found a similar problem from another website which is shown in the attached picture. So, the useful information here are the stoichiometric coefficients of the reaction and the initial amount of 7.49 g of S. The solution is as follows:

Molar mass of S = 32.06 g/mol
Molar mass of SO₃ = 80.06 g/mol

Theo yield of SO₃ = (7.49 g S)(1 mol S/32.06 g)(2 mol SO₃/2 mol S)(80.06 g SO₃/mol) = <em>18.7 g SO₃</em>

You might be interested in
Why is the structure of a molecule important to its function
Scilla [17]

Answer:

It determines how biological molecules recognize and respond to one another with specificity.

Explanation:

A molecule has a characteristic size and shape. The precise shape of a molecule is usually very important to its function in the living cell. Molecular shape is crucial in biology because it determines how biological molecules recognize and respond to one another with specificity.

3 0
3 years ago
) If you started with 2.3182 g of 3-nitrophthalic acid and had a 93% yield of 3-nitrophthalhydrazide, how many grams of 3-nitrop
MArishka [77]

Answer: 1.8124 g of 3-nitrophthalhydrazide were recovered.

Explanation:

The balanced chemical reaction will be :

C_8H_5NO_6+N_2H_4\rightarrow C_8H_5N_3O_4+2H_2O

moles of 3-nitrophthalic acid  = \frac{\text {given mass}}{\text {molar mass}}=\frac{2.3182g}{211.13g/mol}=0.0110mol

As 1 mole of 3-nitrophthalic acid gives = 1 mole of 3-nitrophthalhydrazide

0.0110 moles of 3-nitrophthalic acid gives = \frac{1}{1}\times 0.0110=0.0110 mole of 3-nitrophthalhydrazide

mass of 3-nitrophthalhydrazide = moles\times {\text {molar mass}}=0.0110mol\times 177.16g/mol=1.9488g

As the percentage yield is 93% , the mass of 3-nitrophthalhydrazide recovered = \frac{1.9488\times 93}{100}=1.8124g

Therefore 1.8124 g of 3-nitrophthalhydrazide were recovered.

4 0
2 years ago
Which of the subshells below do not exist due to the constraints upon the angular momentum quantum number?A) 2dB) 2sC) 2pD) all
Gnom [1K]

Answer:

  • Option A): <em>Due to the constraints upton the angular momentum quantum number, the subshell </em><u><em>2d</em></u><em> does not exist.</em>

Explanation:

The <em>angular momentum quantum number</em>, identified with the letter l (lowercase L),  number is the second quantum number.

This number identifies the shape of the orbital or <em>kind of subshell</em>.

The possible values of the angular momentum quantum number, l, are constrained by the value of the principal quantum number n: l can take values from 0 to n - 1.

So, you can use this guide:

Principal quantum   Angular momentum         Shape of the orbital

number, n                 quantum number, l

         1                                      0                             s

         2                                     0, 1                          s, p

         3                                     0, 1, 2                      s, p, d

Hence,

  • <u>the subshell 2d (n = 2, l = 2) is not feasible</u>.

  • 2s (option B) is possible: n = 2, l = 0

  • 2p (option C) is possible: n = 2, l = 1

7 0
3 years ago
Calculate the volume of 0.684mol of carbon dioxide at s.t.p. show working
solong [7]

Answer: The volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 1 atm (at STP)

V = Volume of gas = ?

n = number of moles = 0.684

R = gas constant = 0.0821Latm/Kmol

T =temperature =273K   (at STP)

V=\frac{nRT}{P}

V=\frac{0.684\times 0.0821L atm/K mol\times 273K}{1atm}

V=15.3L

Thus the volume of 0.684 mol of carbon dioxide at s.t.p. is 15.3 L

6 0
3 years ago
Calculate the rcf (recipe conversion factor) for a new yield of 80 oz. (5 lbs) blueberry muffin batter. the original yield of th
SCORPION-xisa [38]

The rcf (recipe conversion factor)=  0.6

<h3>What is the rcf (recipe conversion factor)?</h3>
  • The conversion factor approach is the most typical technique for modifying recipes.
  • Finding a conversion factor and multiplying the ingredients in the original recipe by that factor are the only two steps needed to do this.
  • Remember that the conversion factor will be larger than 1 if you are raising your amounts to be sure you are finding it correctly.
  • The factor will be less than 1 if your amounts are being decreased. Use the conversion factor approach if you come across a recipe that is written in a standard format.
  • The production of phenolic monomers from lignin is effective and selective when done using reductive catalytic fractionation (RCF).

How this is calculated?

Conversion Factor = New Yield ÷ Old Yield

 =80/134

 =0.5970

 =0.6(rounded to nearest tenth)

To know more about the recipe conversion factor (RCF),refer:

brainly.com/question/23841906

#SPJ4

8 0
2 years ago
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