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Kitty [74]
3 years ago
11

The concentration of a biomolecule inside a rod-shaped prokaryotic cell is 0.0027 m. calculate the number of molecules inside th

e cell, which is 4.4 μm long and 1.2 μm in diameter.
Chemistry
1 answer:
mash [69]3 years ago
4 0

Answer : The number of molecules inside the cell is, 8.08\times 10^6

Solution :

First we have to calculate the volume of biomolecule cell.

Volume = Area of the base of the cell × length of the cell

V=\pi r^2\times h

where,

V = volume of the biomolecule cell

r = radius of the cell = \frac{Diameter}{2}=\frac{1.2}{2}=0.6\mu m

h = length of the cell = 4.4\mu m

Now put all the given values in the above volume formula, we get

V=\frac{22}{7}\times (0.6\mu m)^2\times (4.4\mu m)=4.978\mu m^3=4.978\times 10^{-15}L

conversion : (1\mu m^3=10^{-15}L)

Now we have to calculate the moles of a biomolecule of the cell.

Molarity=\frac{Moles}{Volume}\\\\Moles=Molarity\times Volume=(0.0027mole/L)\times (4.976\times 10^{-15}L)=0.01343\times 10^{-15}moles

Now we have to calculate the number of molecules inside the cell.

\text{Number of molecules}=Moles\times (6.022\times 10^{23})\\\\\text{Number of molecules}=(0.01343\times 10^{-15})\times (6.022\times 10^{23})=8.08\times 10^6

Therefore, the number of molecules inside the cell is, 8.08\times 10^6

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