Answer:
6 kg
Explanation:
F=ma
F is Force(newtons)
m is mass(kg)
a is acceleration(m/s^2)
Plug in the numbers
3000 = m(500)
divide both sides by 500 to cancel out the 500.
3000/500=6
6 = m
6kg is the mass
Answer:
<h3>
The coefficient of kinetic friction between the puck and the ice is
0.12</h3>
Explanation:
Given :
Initial speed ![v_{o} = 9.5 \frac{m}{s}](https://tex.z-dn.net/?f=v_%7Bo%7D%20%3D%209.5%20%5Cfrac%7Bm%7D%7Bs%7D)
Displacement
m
From the kinematics equation,
![v^{2} - v^{2} _{o} = 2ax](https://tex.z-dn.net/?f=v%5E%7B2%7D%20-%20v%5E%7B2%7D%20_%7Bo%7D%20%20%3D%202ax)
Where
final velocity, in our example it is zero (
),
acceleration.
![a =- \frac{90.25}{ 2 \times 37.4}](https://tex.z-dn.net/?f=a%20%3D-%20%5Cfrac%7B90.25%7D%7B%202%20%5Ctimes%2037.4%7D)
![a =- 1.21 \frac{m}{s^{2} }](https://tex.z-dn.net/?f=a%20%3D-%201.21%20%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%20%7D)
From the formula of friction,
![F =- \mu _{k } N](https://tex.z-dn.net/?f=F%20%3D-%20%5Cmu%20_%7Bk%20%7D%20N)
Minus sign represent friction is oppose the motion
Where
( normal reaction force )
( ∵
)
So coefficient of friction,
![\mu_{k} = \frac{1.21}{9.8}](https://tex.z-dn.net/?f=%5Cmu_%7Bk%7D%20%3D%20%5Cfrac%7B1.21%7D%7B9.8%7D)
![\mu_{k} = 0.12](https://tex.z-dn.net/?f=%5Cmu_%7Bk%7D%20%3D%200.12)
Therefore, the coefficient of kinetic friction between the puck and the ice is
0.12 .
If the nonmetal is reacting with atom of another nonmetal, then it shares electrons with the other atom in form of a covalent bond.
If the nonmetal is reacting with an atom metal, then the nonmetal gains an electron from the metal atom, it's called ionic bond.
I am pretty sure that the only statement which is true for particles of the medium of an earthquake P-wave is being shown in the option : b)vibrate parallel to the wave, forming compressions and rarefactions. As you know, <span> it can be formed in two ways : from alternating </span>compressions<span> and </span>rarefactions<span> or </span><span>primary wave. I bet you will agree with me.</span>