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Ray Of Light [21]
3 years ago
14

What type of energy is at work when mini-blinds are being raised or lowered

Physics
1 answer:
ohaa [14]3 years ago
4 0
The type of energy that is ar work when blinds are being raised or lowered is potential energy. because potential energy is the energy stored in an object due to its vertical position, the main cause of the potential energy is the acceleration due to gravity. so that is why its formual is PE = mgh
where m is the mass, g is the acceleration due to gravity and h is the height
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A real heat engine operates between temperatures tc and th. during a certain time, an amount qc of heat is released to the cold
tino4ka555 [31]

q_{c} = Heat released to cold reservoir

q_{h} = Heat released to hot reservoir

W_{max} = maximum amount of work

t_{c} = temperature of cold reservoir

t_{h} = temperature of hot reservoir

we know that

\frac{q_{c}}{q_{h}}=\frac{t_{c}}{t_{h}}

q_{h} = (\frac{t_{h}}{t_{c}})q_{c}                                eq-1

maximum work is given as

W_{max} = q_{h} - q_{c}

using eq-1

W_{max} =  (\frac{t_{h}}{t_{c}})q_{c} - q_{c}



6 0
3 years ago
it takes 560s for a runner to complete one circular lap, moving at a speed of 6.00 m/s. what is the radius of a track?
Lostsunrise [7]

Answer:

534.8 meters

Explanation:

Use T=(2*pi*r)/v

560=(2*pi*r)/6

3360=2*pi*r

1680=pi*r

534.8 meters=radius

4 0
3 years ago
A camera takes a properly exposed photo with a 4.0 mm diameter aperture and a shutter speed of 1/1000 s. If the photographer foc
hoa [83]

Answer:

option E

Explanation:

given,

diameter = 4 mm

shutter speed = 1/1000 s

diameter of aperture = ?

shutter speed = 1/250 s

exposure time to the shutter time

E V = log_2(\dfrac{N^2}{t})

N is the diameter of the aperture and t is the time of exposure

now,

log_2(\dfrac{N^2}{t_1})=log_2(\dfrac{N^2}{t_2})

\dfrac{N_1^2}{t_1}=\dfrac{N_2^2}{t_2}

inserting all the values

\dfrac{4^2}{1000}=\dfrac{N_2^2}{250}

      N₂² = 4

      N₂ = 2 mm

hence , the correct answer is option E

4 0
3 years ago
The greatest pull of a magnet is near its poles.<br><br> True<br> False
DIA [1.3K]
False because opposites attract. :)
6 0
3 years ago
Read 2 more answers
A person is standing on a level floor. His head, upper torso, arms, and hands together weigh 458 N and have a center of gravity
Step2247 [10]

Answer:

the location of the center of gravity for the entire body is 1.08 m

Explanation:

Given the data in the question;

w1 = 458 N, y1 = 1.34 m

w2 = 120 N, y2 = 0.766 m

w3 = 89.8 N, y2 = 0.204 m

The location arrangement of the body part is vertical, locate the overall centre of gravity by simply replacing the horizontal position x by the vertical position y as measured relative to the floor.

so,

Y_{centre of gravity} = (w1y1 + w2y2 + w3y3 ) / ( w1 + w2 + w3 )

so we substitute in our values

Y_{centre of gravity} = (458×1.34 + 120×0.766 + 89.8×0.204 ) / ( 458 + 120 + 89.8 )

Y_{centre of gravity} = 723.9592 / 667.8

Y_{centre of gravity} = 1.08 m

Therefore, the location of the center of gravity for the entire body is 1.08 m

5 0
2 years ago
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