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wolverine [178]
2 years ago
12

When solving a quadratic equation by using the square root method, and the final step results in square-rooting a “perfect squar

e” then the quadratic has ______________________.
Mathematics
1 answer:
Elena L [17]2 years ago
4 0

Answer:

Step-by-step explanation:

we're asked to solve the equation two x squared plus three is equal to 75 so in this situation it looks like we might be able to isolate the x squared pretty simply because there's only one term that involves the next year it's only this x squared term so let's try to do that so let me just rewrite it we have two x squared plus three is equal to 75 I'm going to try to isolate this x squared ...

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(5ab-4a-6)-(4ab-1) find the sum please fast
jekas [21]

We need to get rid of expression parentheses.

If there is a negative sign in front of it,

each term within the expression changes sign.

Otherwise, the expression remains unchanged.

Numerical 'like' terms will be added. There is only one group of like terms

the answer is: ab-4a-5 

<span />
7 0
2 years ago
Please help thank you so so so much <br><br> there is more than one answer
Luden [163]

Answer:

B and C work. A and D do not.

Step-by-step explanation:

This is one of those questions that you have to go through each answer to see what the results are. You don't have to go far to eliminate A and D so let's do that first.

A]

5n + 6

Let n = 1

5(1) + 6

5 + 6= 11

However there is trouble beginning with n = 2

5*2 + 6

10 + 6

16     All you need is one wrong answer and the choice is toast. So A won't work.

================

Try D

6(n - 1)+ 5

n=0

6*(-1) + 5

-6 + 5

- 1

And D has been eliminated with just 1 attempt. n= 2 or n = 1 would be even worse.  D is not one of the answers.

=============

B

Let n = 1

6(1) + 5

6 + 5

11 The first term works.

n = 2

6*(2) + 5

12 + 5

17 and n = 2 works as well. Just in case it is hard to believe, let's try n = 3 because so far, everything is fine.

n = 3

6*(3) + 5

18 + 5

23 And this also works. I'll let you deal with n = 4

========

C

n = 0

6(0 + 1) + 5

6*1 + 5

6 + 5

11

n = 1

6(1 + 1) + 5

6*2 + 5

12 + 5

17 which works.

So C is an answer.

4 0
3 years ago
Aaron has n pencils
galina1969 [7]

Answer:

x=3n

Step-by-step explanation:

three times as many pencils as ben = 3n

not sure why chloe was included

6 0
3 years ago
Find the y intercepts I'll mark the brainliest<br>​
vivado [14]

Answer:

1. (0,-2)

2. (0,8)

3. (0,7)

4. (0 , \frac{1}{2})

5. (0,-3.5)

6. (0,-4)

7. (0,0)

8. (0,-4)

9. (0,5)

10. (0,0)

Step-by-step explanation:

there are 10 boxes in total, slope is y = mx + b

the slope is always the constant.

constant: number without a variable.

y - intercept:

y = mx + <u>b</u>

<u>if there is nothing after the slope it means the y -intercept is 0</u>

<u><em>The Kid Laroi</em></u>

7 0
3 years ago
The sum of two numbers is 9.9, and the sum of the squares of the numbers is 53.21. What are the numbers?
Snezhnost [94]

Answer:

There are two possibilities:

x_{1} = 3.5 and y_{1} = 6.4

x_{2} = 6.4 and y_{2} = 3.5

Step-by-step explanation:

Mathematically speaking, the statement is equivalent to this 2-variable non-linear system:

x + y = 9.9

x^{2} + y^{2} = 53.21

First, x is cleared in the first equation:

x = 9.9 - y

Now, the variable is substituted in the second one:

(9.9-y)^{2} + y^{2} = 53.21

And some algebra is done in order to simplify the expression:

98.01-19.8\cdot y +2\cdot y^{2} = 53.21

2\cdot y^{2} -19.8\cdot y +44.8 = 0

Roots are found by means of the General Equation for Second-Order Polynomials:

y_{1} \approx \frac{32}{5} and y_{2} \approx \frac{7}{2}

There are two different values for x:

y = y_{1}

x_{1} = 9.9-6.4

x_{1} = 3.5

y = y_{2}

x_{2} = 9.9 - 3.5

x_{2} = 6.4

There are two possibilities:

x_{1} = 3.5 and y_{1} = 6.4

x_{2} = 6.4 and y_{2} = 3.5

5 0
3 years ago
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