Question

above shows a balloon full of gas which has a volume of 120.0ml at 300.0k assuming pressure remains constant , what is the voume of the balloon if the temperature of the gas increases to 320.0k?

Answer 1

128 ml  is the voume of the balloon if the temperature of the gas increases to 320.0k.

Explanation:

given that:

T1 (initial temperature) = 300K

V1 ( initial volume) =  120ml

T2 (final temperature) = 320 K

V2 (final volume) = ?

Pressure remained constant throughout the process.

From the equation

$\frac{P1V1}{T1}$ = $\frac{P2V2}{T2}$

Since pressure is constant the equation will be:

$\frac{V1}{T1}$ = $\frac{V2}{T2}$

V2 = $\frac{V1 X T2}{T1}$

    Putting the values in the above formula:

V2 = $\frac{120 X 320}{300}$

     = 128 ml

128 ml is the volume of the gas if temperature increases from 3OO K to 320k