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Svetlanka [38]
3 years ago
6

above shows a balloon full of gas which has a volume of 120.0ml at 300.0k assuming pressure remains constant , what is the voume

of the balloon if the temperature of the gas increases to 320.0k?
Chemistry
1 answer:
trasher [3.6K]3 years ago
4 0

128 ml  is the voume of the balloon if the temperature of the gas increases to 320.0k.

Explanation:

given that:

T1 (initial temperature) = 300K

V1 ( initial volume) =  120ml

T2 (final temperature) = 320 K

V2 (final volume) = ?

Pressure remained constant throughout the process.

From the equation

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Since pressure is constant the equation will be:

\frac{V1}{T1} = \frac{V2}{T2}

V2 = \frac{V1 X T2}{T1}

    Putting the values in the above formula:

V2 = \frac{120 X 320}{300}

     = 128 ml

128 ml is the volume of the gas if temperature increases from 3OO K to 320k

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a

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Explanation:

Magnesium loses two electrons and oxygen gains these electrons so ionic bond is formed

8 0
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A group of giraffes feeds on leaves and grasses during the daytime. Right now, it is dark out and the giraffes are not eating. I
Zanzabum

Answer:

Carbon dioxide is moving out of the living things.

Explanation:

The food materials eaten by living things contain carbon in the form of complex organic matter. When living things feed, they ingest this complex organic material into their bodies.

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During cellular respiration, glucose is broken down to release carbon dioxide. Hence, at night when the giraffe has stopped eating, cellular respiration continues to occur and carbon dioxide is released, that is, carbon dioxide continues to move out of living things at night.

7 0
2 years ago
Why do crisp packets become inflated at high altitudes? Again, explain in as great a detail as possible, using ideas about parti
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3 0
3 years ago
If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the of strontium-90 is ________ yr.
lesantik [10]

The question is incomplete, here is the complete question.

If we start with 1.000 g of strontium-90, 0.805 g will remain after 9.00 yr. This means that the half-life of strontium-90 is ________ yr.

a. 28.8 b. 30.9 c. 35.4 d. 32.2

Answer :  The half-life of strontium-90 is 28.8 years.

Explanation :

This is a type of radioactive decay and all radioactive decays follow first order kinetics.

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken for decay process  = 9.00 year

a = initial amount or moles of the reactant  = 1.000 g

a - x = amount or moles left after decay process  = 0.805 g

Putting values in above equation, we get:

k=\frac{2.303}{9.00}\log\frac{1.00}{0.805}

k=0.0241\text{ year}^{-1}

To calculate the half-life, we use the formula :

k=\frac{0.693}{t_{1/2}}

0.0241\text{ year}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=28.8\text{ years}

Therefore, the half-life of strontium-90 is 28.8 years.

5 0
3 years ago
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