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luda_lava [24]
3 years ago
6

What is the mole fraction of solute and the molal concentration for an aqueous solution that is 16.0% NaOH by mass?

Chemistry
1 answer:
Soloha48 [4]3 years ago
5 0
<span>let's start:

16 g NaOH has 84 g of water 
moles of NaOH =16/40
                          =0.4 
moles of water =84/18
                    = 4.667 
Total moles = 0.4+4.667
                   = 5.067 
mole fraction of NaOH = 0.4/5.067
                                     = 0.0789
Conclusion: 
84 g water will have 0.4 moles of NaOH 
1000g water will have [0.4x 1000]/84
                                  = 4.76 moles
This is called molality.
ENJOY :)

</span>
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djverab [1.8K]

Answer:

See explanation and image attached

Explanation:

Let us examine the statements in the question carefully. First of all, we will discover that the products of the E2 elimination of the both compounds are isomeric. However Y does not undergo SN2 reaction as  X does.

The fact that SN2 reaction does not occur in Y confirms that the bromine atom is attached to a tertiary carbon atom and SN2 reaction does not occur due to steric hinderance. Since X undergoes SN2 reaction in aprotic solvent, the chlorine atom must be attached to a secondary carbon atom.

However, E2 reactions does occur with tertiary alkyl halides when strong bases such as OH^- or RO^- are used.

The question also stated that the catalytic hydrogenation of Z affords 3-ethylpentane.

Putting all these together, the structures of X and Y have been suggested in the image attached to this answer.

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3 years ago
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Answer:

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6 0
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Explanation:

In the annexed picture you can see your same question, just in another format.

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