Explanation :
The balanced chemical reaction is,
The expression for the rates of consumption of the reactants are:
The rate of consumption of 
= ![-\frac{1}{5}\frac{d[Br^-]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7B1%7D%7B5%7D%5Cfrac%7Bd%5BBr%5E-%5D%7D%7Bdt%7D)
The rate of consumption of 
= ![-\frac{d[BrO_3^-]}{dt}](https://tex.z-dn.net/?f=-%5Cfrac%7Bd%5BBrO_3%5E-%5D%7D%7Bdt%7D)
The rate of consumption of 
= ![\frac{1}{6}\frac{d[H^+]}{dt}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B6%7D%5Cfrac%7Bd%5BH%5E%2B%5D%7D%7Bdt%7D)
The expression for the rates of formation of the products are:
The rate of consumption of 
= ![+\frac{1}{3}\frac{d[Br_2]}{dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BBr_2%5D%7D%7Bdt%7D)
The rate of consumption of 
= ![+\frac{1}{3}\frac{d[H_2O]}{dt}](https://tex.z-dn.net/?f=%2B%5Cfrac%7B1%7D%7B3%7D%5Cfrac%7Bd%5BH_2O%5D%7D%7Bdt%7D)
The standard Gibbs free energy of formation of ZnO from Zn is lower than that of CO2 from CO. Therefore, CO cannot reduce ZnO to Zn. Hence, Zn is not extracted from ZnO through reduction using CO
Answer:
The volume of the gas sample at standard pressure is <u>819.5ml</u>
Explanation:
Solution Given:
let volume be V and temperature be T and pressure be P.
1 torr= 1 mmhg
42.2 torr=42.2 mmhg
so,
Now
firstly we need to find the pressure due to gas along by subtracting the vapor pressure of water.
=735-42.2=692.8 mmhg
Now
By using combined gas law equation:
Here 
are standard pressure and temperature respectively.
we have
Substituting value, we get
Hello!
The reaction that the graph represents is
A. Exothermic because Hrxn=-167 kJTo calculate Hrxn we apply the following equation:
Looking at the graph, and at the result of the calculations, we can see that the enthalpy of the products is
lower than the enthalpy of the reagents, because the sign is negative. That means that the reaction
releases energy in the form of heat and that the reaction is
exothermic.
Have a nice day!
Answer:It is false
Explanation:
I took a quiz with this question in it and I chose true but I got it wrong
