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3 years ago

Why does a candle relight if a match is held above the wick just after the flame is blown out?

Chemistry

1 answer:

shutvik [7]3 years ago

5 0

Answer with Explanation:

A candle relights when a match is held above the wick because its trail of smoke still contains some of the wax. When candles are burned, the heat of the flame turns the the wax (which is originally solid) into liquid (commonly near the wick) and then evaporates as gas. The vaporized wax actually protect the wick and this is the reason why it is not burned. So, when you put off a candle, the vaporized wax is still present near the wick. This, remember, holds heat and light energy. Thus, this explains why the candle can be relighted once you hold a match above the wick. It then allows the match to ignite.

Thus, this explains the answer.

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3 years ago

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2 years ago

A super slow snail can travel 2.2cm in one minute. How far (in pm) can it travel in 24 hours? Please round to appropriate number

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Answer : The distance covered by slow snail in 24 hours is $3.2\times 10^{13}pm$

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As we are given that the a slow snail can travel 2.2 cm in 1 minute. Now we have to calculate the distance covered by slow snail in 24 hours.

First we have to convert 24 hours in minutes.

Conversion used : (1 hour = 60 minutes)

As, 1 hour = 60 minutes

So, 24 hour = 24 × 60 minutes

= 1440 minutes

Now we have to calculate the distance covered by slow snail in 24 hours.

In 1 minute, the distance covered by slow snail = 2.2 cm

In 1440 minute, the distance covered by slow snail = 1440 × 2.2 cm

= 3168 cm

= $3.2\times 10^3cm$

Now we have to convert 'cm' into 'pm'.

Conversion used : $1cm=10^{10}pm$

As, $1cm=10^{10}pm$

So, $3.2\times 10^3cm=\frac{3.2\times 10^3cm}{1cm}\times 10^{10}pm=3.2\times 10^{13}pm$

Therefore, the distance covered by slow snail in 24 hours is $3.2\times 10^{13}pm$

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3 years ago