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3 years ago

Sprite: When mixed with red cabbage water, resulting solution turned red.

Chemistry

2 answers:

Naddika [18.5K]3 years ago

8 0

<h2>Answer : Option B) Watermelon Juice.</h2><h3>Explanation :</h3>

When the experiment is conducted using the red cabbage water (already pink/purple in color) in three parts using sprite, watermelon juice and egg whites; the effect on the red cabbage water was in red color, purple (Neutral) and green in color respectively.

These color indicates -

Red - Acid

Pink/purple - Neutral

Green - Base.

So, when watermelon juice was mixed with the red cabbage water it didn't changed the color, which clearly indicates that watermelon juice was neutral in nature.

german3 years ago

6 0

A) Egg Whites is the correct answer

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2) Calculate the mass(g) of the following substances: b) 0.119 mole MgCl2

VARVARA [1.3K]

Answer:

MgCl2 = 24 + 2(35.5)

= 95

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3 years ago

Why are the densities of corn syrup and gasoline expressed as a range of values

balu736 [363]

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3 years ago

Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)

Natali [406]

Answer:

a) 1.44g

b) 77.3%

Explanation:

1. Chemical balanced equation (given)

$NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)$

2. Mole ratio

$1molNaOH(aq):1molKHP(s)$

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

3. Find the number of moles in 72.14 mL of the base

$Molarity=\text{number of moles of solute}/\text{volume of solution in liters}$

$\text{Volume of solution}=72.14mL=0.07214liters$

$\text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol$

4. Find the number of grams of KHP that reacted

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

mass = number moles × molar mass = 0.007055mol × 204.23g/mol

mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

5. Find the percentage of KHP in the sample

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

% = (mass of substance / mass of sample) × 100

% = (1.4408g/ 1.864g) × 100 = 77.3%

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3 years ago