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Aleksandr [31]
3 years ago
10

Write the slope-intercept form of the equation of the line; (-5,-4) and prep. To y equals 5x plus 1

Mathematics
1 answer:
ohaa [14]3 years ago
4 0

Answer:

y=-\frac{1}{5} x-5

Step-by-step explanation:

The given line is defined by:  y=5x+1, where we see that the slope is 5 and the y-intercept 1.

In order to find a line perpendicular to the given one, we need it to have a slope that is the "opposite of the reciprocal" of the given slope.

"Opposite" means it would have its sign inverted (in our case from positive to negative); and "reciprocal means that instead of 5, it would be its reciprocal: \frac{1}{5}.

We can write this new line with such slope, and try to find its y-intercept (b) by using the given condition that requires it to go through the point (-5,-4) on he plane:

y=-\frac{1}{5} x+b

we require then that when x=-5, the value of y=-4.

Therefore: -4=-\frac{1}{5} (-5)+b\\-4=\frac{5}{5} +b\\-4=1+b\\b=-4-1=-5

Then our final answer is that the new line should have the form: y=-\frac{1}{5} x-5

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A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane  so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So,   w  = k V , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h  distance,  pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is,   V= \frac{1}{3}  *A* 5

So, weight of original pyramid,  W = k *(\frac{1}{3}  *A* 5) = 800

Volume of small pyramid is,  v = \frac{1}{3}* a* h

So, weight of small pyramid, w = k*(\frac{1}{3}* a* h)=400

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So,  \frac{a}{A}  = (\frac{h}{5}) ^{2}

       a = (\frac{h}{5} )^{2}A

Substituting value of a in  equation k*(\frac{1}{3}* a* h)=400

So, k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400

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Since, (k *\frac{1}{3}  *A* 5) = 800, substitute in above equation.

    So, 800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet

Learn more:

brainly.com/question/17950304

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Answer:

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Step-by-step explanation:

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