Answer:
![y=-\frac{1}{5} x-5](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B5%7D%20x-5)
Step-by-step explanation:
The given line is defined by:
, where we see that the slope is 5 and the y-intercept 1.
In order to find a line perpendicular to the given one, we need it to have a slope that is the "opposite of the reciprocal" of the given slope.
"Opposite" means it would have its sign inverted (in our case from positive to negative); and "reciprocal means that instead of 5, it would be its reciprocal:
.
We can write this new line with such slope, and try to find its y-intercept (b) by using the given condition that requires it to go through the point (-5,-4) on he plane:
![y=-\frac{1}{5} x+b](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B5%7D%20x%2Bb)
we require then that when
, the value of
.
Therefore: ![-4=-\frac{1}{5} (-5)+b\\-4=\frac{5}{5} +b\\-4=1+b\\b=-4-1=-5](https://tex.z-dn.net/?f=-4%3D-%5Cfrac%7B1%7D%7B5%7D%20%28-5%29%2Bb%5C%5C-4%3D%5Cfrac%7B5%7D%7B5%7D%20%2Bb%5C%5C-4%3D1%2Bb%5C%5Cb%3D-4-1%3D-5)
Then our final answer is that the new line should have the form: ![y=-\frac{1}{5} x-5](https://tex.z-dn.net/?f=y%3D-%5Cfrac%7B1%7D%7B5%7D%20x-5)