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madreJ [45]
3 years ago
9

Which one of the following statements is true of perpendicular lines? A. They intersect to form an obtuse angle. B. They interse

ct at one point. C. They never intersect. D. They intersect to form an acute angle.
Mathematics
2 answers:
quester [9]3 years ago
6 0
They intersect at one point
ladessa [460]3 years ago
4 0

Answer:

B. They intersect at one point.

Step-by-step explanation:

Perpendicular lines intersect at one point at 90 degrees.

Therefore, we ignore options A) , C) and D)

Perpendicular means 90 degrees

Therefore, answer is B. They intersect at one point.

Hope this will helpful.

Thank you.

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Nastasia [14]

Answer: x=10

Step-by-step explanation:

7776^{x+5}=216^{3x-5}

6^{5(x+5)}=6^{3(3x-5)}

5(x+5)=3(3x-5)

5x+25=9x-15

25=4x-15

4x=40

x=10

8 0
1 year ago
A man looked in his wallet and found he had 3 more $5 bills than $10 dollar bills. He had a total of $75. How many of each kind
Neko [114]

Answer:

Four 10s and seven 5s

Step-by-step explanation:

If you start with one 10, you have to have four 5s. After that you add one of each until you reach 75

3 0
3 years ago
Compare a loss of 36 yards to a loss of 48 yards
gavmur [86]
The total loss is 84 loss (-84). 
7 0
3 years ago
if u went to a grocrey store and bought four item. Which of the containers would hold less than 500ml? A. Laundry detergent. B.
allsm [11]
500mL is basically your average Dasani or Fiji water. So D) a gallon of milk is a bit too big, along with A, so we can cross those two out. B) A cup of yogurt is too small- one cup is only 200mL. So our answer would be C) A bottle of salad dressing.

5 0
3 years ago
A motorboat is capable of traveling at a speed of 14 miles per hour in still water. On a particular day, it took 15 minutes long
Anon25 [30]

By solving a system of equations we will find that the rate of current in the stream is S = 2 mi/h.

When the motorboat travels downstream, the total velocity will be the velocity of the motorboat in still water plus the velocity of the stream, while if the motorboat travels upstream, we have the velocity of the stream subtracted.

So upstream the speed is:

(14 mi/h - S)

Downstream the speed is:

(14 mi/h + S)

Where S is the rate of current in the stream.

We know that downstream it takes 15 minutes more to travel 12 miles, then we can write the system of equations:

(14 mi/h + S)*T = 12 mi

(14 mi/h - S)*(T - 15 min) = 12 mi

To solve this, we need to isolate one of the variables in one of the equations, I will isolate T in the first one:

T = (12 mi)/(14 mi/h + S)

Replacing that in the other equation we will get:

(14 mi/h - S)*((12 mi)/(14 mi/h + S) - 15 min) = 12 mi

Now we can solve this for S. Now we can multiply both sides by (14 mi/h + S).

(14 mi/h - S)*12 mi  - (14 mi/h + S)*(14 mi/h - S)*(- 15 min) = 12 mi*(14 mi/h + S)

Also notice that the speeds are in hours, so we can rewrite:

- 15 min = -0.25 h

(14 mi/h - S)*12 mi  - (14 mi/h + S)*(14 mi/h - S)*(- 0.25 h) = 12 mi*(14 mi/h + S)

168 mi^2/h - 12mi*S  + 49mi^2/h + 0.25h*S^2 = 168mi^2/h + 12mi*S

- 12mi*S  + 49mi^2/h - 0.25h*S^2 = 12mi*S

-24mi*S -  0.25h*S^2  + 49mi^2/h = 0

This is a quadratic equation, the solutions are:

S = \frac{24mi \pm \sqrt{(-24mi)^2 - 4*(49mi^2/h)*(-0.25h)}  }{2*-0.25h} \\\\S =  \frac{24mi \pm 25 mi  }{-0.5h}

We only take the positive solution, so we get:

S = (24 mi - 25 mi)/(-0.5 mi) = 2 mi/h

The rate of current in the stream is 2 mi/h.

If you want to learn more, you can read:

4 0
2 years ago
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