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nekit [7.7K]
3 years ago
13

A 75.0 kg man sits on a massless cart that is on a horizontal surface. The cart is initially stationary and it can move without

friction or air resistance. The man throws a 5.00 kg stone in the positive direction, applying a force to it so that it has acceleration +3.50 m/s2 as measured by a nearby observer on the ground. What is the man's acceleration during the throw, as seen by the same observer? Be careful to use correct signs.
Physics
1 answer:
Anna11 [10]3 years ago
6 0

Answer:0.233 m/s^2

Explanation:

Given

Mass of man m=75 kg

mass of stone m_0=5 kg

acceleration of stone a=3.5 m/s^2

To provide a acceleration of 3.5 m/s^2[/tex] he must exert a force of

F=m_0\times a=5\times 3.5=17.5 N

same Force is exerted by stone on cart

17.5=m\times a

a=\frac{17.5}{75}=0.233 m/s^2

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sergey [27]
More cool stars produce much of their light in the red part of the spectrum, so you see them, and bam, the color red. More hot stars, however, produce much more of their light in the green and or yellow spectrums, with much more tinier amounts of red / blue. This balance of the colors, your eye, sees simply as white. The more hot something is, the greater frequency of radiation it produces! Blue light has a higher frequency than red light, so the stars that glow red are cooler, than the stars that glow blue. :)

Hope this helped!
8 0
3 years ago
How many joules of work are done on an object when a force of 10 N pushes it 5 m?
zhenek [66]

Answer:

option C

Explanation:

given,                            

Force on the object = 10 N

distance of push = 5 m

Work done = ?              

we know,              

work done is equal to Force into displacement.

W = F . s            

W = 10 x 5              

W = 50 J                

Work done by the object when 10 N force is applied is equal to 50 J

Hence, the correct answer is option C

5 0
3 years ago
Identify the  traces on the oscilloscope screen and explain what happens to the pitch of the sound in both A and B. Mention your
jolli1 [7]

Answer:

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Explanation:

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5 0
2 years ago
A 7.94-nC charge is located 1.77 m from a 4.14-nC point charge. (a) Find the magnitude of the electrostatic force that one charg
STatiana [176]

Answer:

F=94.32*10⁻⁹N  , The force F is repusilve because both charges have the same sign (+)

Explanation:

Two point charges (q₁, q₂) separated by a distance (d) exert a mutual force (F) whose magnitude is determined by the following formula:  

F=K*q₁*q₂/d² Formula (1)  

F: Electric force in Newtons (N)

K : Coulomb constant in N*m²/C²

q₁,q₂:Charges in Coulombs (C)  

d: distance between the charges in meters(m)

Equivalence  

1nC= 10⁻⁹C

Data

K=8.99x10⁹N*m²/C²

q₁ = 7.94-nC= 7.94*10⁻⁹C

q₂= 4.14-nC=  4.14 *10⁻⁹C

d= 1.77 m

Magnitude of the electrostatic force that one charge exerts on the other

We apply formula (1):

F=8.99x10^{9} *\frac{7.94*10^{-9} *4.14 *10^{-9} }{1.77^{2} }

F=94.32*10⁻⁹N  , The force F is repusilve because both charges have the same sign (+)

7 0
3 years ago
I need help on this.​
lana [24]

Answer:

The speed change during the 45-minute trip is 20[mph]

Explanation:

When we see the speed at the 45 minutes this is 20 [mph] and at the 0 minutes the speed is 0 [mph].

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In the attached image we can see the different figures. In fig 1 we can see the bicycle's speed after 10 minutes when the speed becames constant.

In the fig. 2 we can find the graph when the biker stopped at 30 minutes and took a 15-minute break.

Figures 3 and 4, show the differences when a horizontal line is traced on a position vs time graph, and when the horizontal line is traced in a speed vs time graph.

For fig 3 we can conclude that the body is not moving therefore there is no velocity or acceleration. And for the fig 4, we can realize that the area under the horizontal line represents a displacement during the respective interval of time.

3 0
3 years ago
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