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I am Lyosha [343]
3 years ago
9

The moon sun is directly overhead at the equator during ( a solstice or an equinox)?.

Physics
1 answer:
mina [271]3 years ago
4 0
I think it equinox but I’m not 100% sure
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Hi please please help me you’ll get points and I’ll give you brainliest
leonid [27]

Answer:

see below

Explanation:

Question 1)

57kg to ug

126\:Kg(\frac{1*10^{9}ug }{1kg} )\\\\=126(10^{9} )\\\\=126,000,000,000 ug                                  (there are 9 zeros)

Question 2)

126lbs to N

126lbs(\frac{4.45N}{1lb} )\\\\=126(4.45N)\\\\=506.7N

7 0
3 years ago
Calculate the east component of a resultant 32.5 m/s, 35.0° east of north.
ValentinkaMS [17]

Answer:

East component is: 18.64 m/s

Explanation:

If the resultant is 32.5 m/s directed 35 degrees east of north, then we use the sin(35) projection to find the east component of the velocity:

East component = 32.5 m/s * sin(35) = 18.64 m/s

4 0
3 years ago
What is the meaning of inertia?
SSSSS [86.1K]
Inertia is the property of all matter by which it tends to remain
in constant, uniform motion unless acted on by external force.
7 0
3 years ago
Read 2 more answers
UCaShoTLLOuuj9D4vqFtTpSQ<br><br> search
Bond [772]

Answer:

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Explanation:

4 0
3 years ago
An airplane traveling at 201 m/s makes a turn. What is the smallest radius of the circular path (in km) that the pilot can make
egoroff_w [7]

Answer:

the smallest radius of the circular path is 8.1 km

Explanation:

The computation of the smallest radius of the circular path is given below:

Given that

V = Velocity = 201 m/s

a_c = acceleration = 5 m/s^2

radius = ?

As we know that

a_c = V^2 ÷ r

5 = 201^2 ÷ r

r = 201^2 ÷ 5

= 8,080.2 g

= 8.1 km

Hence, the smallest radius of the circular path is 8.1 km

4 0
2 years ago
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