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bagirrra123 [75]
3 years ago
9

An object of mass 3.00 kg, moving with an initial velocity of 5.05 m/s, collides with and sticks to an object of mass 2.76 kg wi

th an initial velocity of -3.66 m/s. Find the final velocity of the composite object.
Physics
1 answer:
Lynna [10]3 years ago
6 0

Answer:

0.752 m/s

Explanation:

m1 = 3.00kg

u1 = 5.05m/s

m2 = 2.76kg

u2 = -3.66m/s

According to the law of conservation of momentum,

m1u1 + m2u2 = (m1+m2)v

3(5.05) + 2.76(-3.66) = (5.05+2.76)v

15.15 - 9.2736 = 7.81v

5.8764 = 7.81v

v = 5.8764/7.81

v = 0.752m/s

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Answer:Racquet force is twice of Player force

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Given

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F_{racquet}=\frac{80m}{\Delta t}-----1

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4 years ago
A car drives 215 km east and then 45 km north. What is the magnitude of the car’s displacement? Round your answer to the nearest
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Displacement = (straight-line distance between the start point and end point) .

Since the road east is perpendicular to the road north,
the car drove two legs of a right triangle, and the magnitude
of its final displacement is the hypotenuse of the triangle.

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8 0
3 years ago
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motikmotik

Answer:

0.79 s

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\sum F_x:f_{max}=ma_x\\\sum F_y:N-mg=0

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8 0
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2. What is the speed of section A? Section B? Section C?
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Molecules in a gas move faster than in a liquid.

hope it helps.
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3 years ago
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