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True [87]
3 years ago
15

Driving along in your car, you take your foot off the gas, and your speedometer shows a reduction in speed. Describe an inertial

frame in which your car was speeding up during that same period of time. Remember, an inertial frame is one whose speed and direction are not changing.
Physics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

  v ’= v + v₀

a system can be another vehicle moving in the opposite direction.

Explanation:

In an inertial reference frame the speed of the vehicle is given by the Galileo transformational

          v ’= v - v₀

where v 'is the speed with respect to the mobile system, which moves with constant speed, v is the speed with respect to the fixed system and vo is the speed of the mobile system.

The vehicle's speedometer measures the harvest of a fixed system on earth, in this system v decreases, for a system where v 'increases it has to be a system in which the mobile system moves in the negative direction of the x axis, whereby the transformation ratio is

        v ’= v + v₀

Such a system can be another vehicle moving in the opposite direction.

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During either one, the sun, moon, and Earth are lined up in the same straight line. The difference is whether the moon or the Earth is the one in the "middle".
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4 years ago
2. A company hires a security firm to patrol their stores and watch out for thieves. What is this an example of?
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Answer:

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Explanation:

4 0
3 years ago
You are standing a distance of 17.0 meters from the center of a merry-go-round. The merry-go-round takes 9.50 seconds to go comp
GenaCL600 [577]

Answer:

(a)11.24 m/s

(b)7.44 m/s

(c)409 N

(d)539.55\mu

(e) 0

Explanation:

The period for 1 circle 2\pi of the merry go around is 9.5s. It means the angular speed is:

\omega = \theta / t = 2\pi / 9.5 \approx 0.661 rad/s

(a)The speed is

v = \omega * R = 0.661 * 17 = 11.24 m/s

(b) Centripetal acceleration:

a = \frac{v^2}{R} = \frac{11.24^2}{17} = 7.44 m/s^2

(c) Magnitude of the force that keeps you go around at this acceleration

F = ma = 55 * 7.44 = 409 N

(d) let the coefficient of friction by \mu. The frictional force shall be this coefficient multiplied by normal force reverting gravity of the man

F_f = mg\mu = 55*9.81\mu = 539.55\mu

3 0
3 years ago
Guys answer with a clear explanation and plzz don't spam.
timama [110]

Answer:

20.7N

Explanation:

There are many students who can not get answers step by step and on time

So there are a wats up group where you can get help step by step and well explained by the trusted experts.

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3 0
3 years ago
6. 498.82 mg comverted to kg​
Ivanshal [37]

Answer:

0.00049882 kg

........................

6 0
3 years ago
Read 2 more answers
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