Select the statement that best describes how the forces relate. (2 points)
2 answers:
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Answer:
The potential for r > rb is equal to zero.
Explanation:
For r > rb, the potential is:
Then, the net potential is:
Answer:
Vf = 210 [m/s]
Av = 105 [m/s]
y = 2205 [m]
Explanation:
To solve this problem we must use the following formula of kinematics.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 0 (released from the rest)
g = gravity acceleration = 10 [m/s²]
t = time = 21 [s]
Vf = 0 + (10*21)
Vf = 210 [m/s]
Note: The positive sign for the gravity acceleration means that the object is falling in the same direction of the gravity acceleration (downwards)
The average speed is defined as the sum of the final speed plus the initial speed divided by two. (the initial velocity is zero)
Av = (210 + 0)/2
Av = 105 [m/s]
To calculate the distance we must use the following equation of kinematics
44100 = 20*y
y = 2205 [m]
Answer:
The phase difference between these two waves is 141.1⁰
Explanation:
The displacement of the wave is given as;
Amplitude, A = 2yₓCos(¹/₂Φ)
Since the amplitude of the combination is 1.5 times that of one of the original amplitudes = yₓ = 1.5 × A = 1.5A
A = 2(1.5A)Cos(¹/₂Φ)
A = 3ACos(¹/₂Φ)
¹/₃ = Cos(¹/₂Φ)
(¹/₂Φ) = Cos ⁻(0.3333)
(¹/₂Φ) = 70.55°
Φ = 141.1°
The phase difference between these two waves is 141.1⁰
Answer:
The force constant for each elastic band is 77.93 N/m
Explanation:
Hooke's law of a spring or an elastic band gives the relation between elastic force (Fe) and stretching (x), the magnitude of that force is:
(1)
With k, the elastic force constant. The three elastic bands support the child’s weight (W) and maintain him at rest, so by Newton’s second law for one of the elastic bands:
(2)
(3)
Using (1) on (3):
(4)