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k0ka [10]
4 years ago
11

Select the statement that best describes how the forces relate. (2 points)

Physics
2 answers:
Anarel [89]4 years ago
4 0
"D. Magnetic and electrical forces are similar because they are both related to the interactions between charged particles" best describes how the forces relate.
telo118 [61]4 years ago
3 0
Your answer would be d

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Where are the field poles mounted on an alternator
tia_tia [17]

Explanation:

(D) i think there you go have a good day

8 0
3 years ago
The flowers of the bunchberry plant open with astonishing force and speed, with pollen grains accelerating from rest to 7.5 m/s.
zimovet [89]

Answer:

a) J=7.5*10^{-10}

b) F = 2.5*10^{-6}N

c) The force is 2551.02 times bigger than the weight of the pollen grain.

Explanation:

a) we know that the impulse J is equal to:

J =MV_f-MV_i

where M is the mass, V_f is the final velocity and V_i the initial velocity. So, replacing values, we get:

J =(10^{-10})(7.5m/s)-(10^{-10}(0)

J =(10^{-10})(7.5m/s)

J=7.5*10^{-10}

b) We know that the force is equal to:

F = J/t

where J is the impulse and t the time. So, replacing values, we get:

F = \frac{7.5*10^{-10}}{0.0003}

F = 2.5*10^{-6}N

c) The weight W of the pollen grain is calculated as:

W = 10^{-10}*9.8

W = 9.8*10^{-10}N

So, if we compare the force and the weight of the pollen grain, we get:

\frac{2.5*10^{-6} }{9.8*10^{-10} } =2551.02

it means that the force is 2551.02 times bigger than the weight of the pollen grain.

3 0
3 years ago
Read 2 more answers
Why is there a minimum mass for an object to become a star? smaller objects cannot be detected from earth. smaller objects canno
Julli [10]

Answer:

1. smaller objects cannot generate enough pressure to start hydrogen fusion.

2. 10,000,000

Explanation:

1. Stars are born in stellar nurseries known as nebula. A nebula is cloud of dust and gases. The disk of dust and gases when spins and gathers more and more mass, the temperature and pressure rises. If sufficient mass is gathered and right temperature and pressure is achieved fusion reaction starts and a star is born. Thus, smaller objects cannot generate enough pressure to start hydrogen fusion.

2.  the core of a star must reach a temperature of  <u>10,000,000</u>  degrees Celsius for hydrogen fusion to begin.

Hydrogen fusion reaction in sun is:

_1^1\textrm{H}+_1^1\textrm{H}\rightarrow 1^2\textrm{H}+_{+1}^0\textrm{e}+\text{energy}\\\\_1^2\textrm{H}+_1^1\textrm{H}\rightarrow 2^3\textrm{He}+\text{energy}\\\\_2^3\textrm{He}+_1^1\textrm{H}\rightarrow _2^4\textrm{He}+_{+1}^0\textrm{e}+\text{energy}

Overall reaction for the above series of reactions is given by:

4_1^1\textrm{H}\rightarrow _2^4\textrm{He}+2_{+1}^0\textrm{e}+\text{energy}

3 0
3 years ago
Read 2 more answers
The hot glowing surfaces of stars emit energy in the form of electromagnetic radiation. It is a good approximation to assume tha
belka [17]

Given that,

Energy H=2.7\times10^{31}\ W

Surface temperature = 11000 K

Emissivity e =1

(a). We need to calculate the radius of the star

Using formula of energy

H=Ae\sigma T^4

A=\dfrac{H}{e\sigma T^4}

4\pi R^2=\dfrac{H}{e\sigma T^4}

R^2=\dfrac{H}{e\sigma T^4\times4\pi}

Put the value into the formula

R=\sqrt{\dfrac{2.7\times10^{31}}{1\times5.67\times10^{-8}\times(11000)^4\times 4\pi}}

R=5.0\times10^{10}\ m

(b). Given that,

Radiates energy H=2.1\times10^{23}\ W

Temperature T = 10000 K

We need to calculate the radius of the star

Using formula of radius

R^2=\dfrac{H}{e\sigma T^4\times4\pi}

Put the value into the formula

R=\sqrt{\dfrac{2.1\times10^{23}}{1\times5.67\times10^{-8}\times(10000)^4\times4\pi}}

R=5.42\times10^{6}\ m

Hence, (a). The radius of the star is 5.0\times10^{10}\ m

(b). The radius of the star is 5.42\times10^{6}\ m

8 0
3 years ago
Predict whether sound will would travel faster in air in summer or in winter?
Arisa [49]
In summer because the air in summer is less dense.
8 0
3 years ago
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