Answer:
∴ Q = -7.52kCal
Explanation:
Using the formula for specific heat capacity:
Q = mcΔT
where ΔT = change in temperature (final - initial) = (0 - 100)°C = -100°C
m = mass (g) = 75g
c = specific heat capacity = 4.2 J/g°C in water
⇒ Q = 75 × 4.2 × -100
= -31,500J
But 1J - 0.000239kCal
<u>∴ Q = -7.52kCal</u>
<u />
Let me know if I can be of further assistance.
Nitrogen could form 3 covalent bonds if each of its unpaired electrons participates in one bond.
Nitrogen atom forms 3 bonds based on octet rule, because it has 5 valence electrons. That means it needs 3 bonds or three more electrons.
<h3>Further Explanation;</h3><h3>Chemical bond </h3>
- A bond is a type of force that is formed between atoms of different through the sharing or transfer of electrons.
<h3>Octet rule</h3>
- According to the octet rule for an atom to be stable it must have maximum number of electrons in its outermost energy level. Therefore an atom with four electrons requires four more electrons to attain stability.
<h3>Types of chemical bonds.</h3><h3>Covalent bond </h3>
- This is a type of bond that is formed between non-metal atoms. It is formed as a result of sharing electrons between non-metal atoms involved.
- When atoms involved contribute equal number of electrons to the bond formation, the type of bond is known as covalent bond
- A covalent bond may be a dative covalent bond, when the shared electrons come from one atom.
<h3>Ionic bond </h3>
- This is a type of bond that occurs between metal ions and non-metal ions. Ionic bond occurs as a result of transfer of electrons from one metal atom to another non-metal atom.
- After the transfer of electrons, metal atom loses electron to form a cation while the non-metal atom gains electrons to form an anion.
<h3>
Other types of chemical bonds include;</h3>
- Hydrogen bonds
- Metallic bonds
- Dipole-dipole interactions, etc.
Keywords: Chemical bond, covalent bond, atom
<h3>Learn more about:</h3>
Level: High school
Subject: Chemistry
Topic: structure and bonding
Sub-topic: Covalent bond
Answer:
The heat at constant pressure is -3,275.7413 kJ
Explanation:
The combustion equation is 2C₆H₆ (l) + 15O₂ (g) → 12CO₂ (g) + 6H₂O (l)
= (12 - 15)/2 = -3/2
We have;
Where R and T are constant, and ΔU is given we can write the relationship as follows;
Where;
H = The heat at constant pressure
U = The heat at constant volume = -3,272 kJ
= The change in the number of gas molecules per mole
R = The universal gas constant = 8.314 J/(mol·K)
T = The temperature = 300 K
Therefore, we get;
H = -3,272 kJ + (-3/2) mol ×8.314 J/(mol·K) ×300 K) × 1 kJ/(1000 J) = -3,275.7413 kJ
The heat at constant pressure, H = -3,275.7413 kJ.
Oxidation of D -Ribose in presence of hypobromous acid gives D-Ribonic acid
Answer:
heya!!!
Explanation:
In atomic physics, the Rutherford–Bohr model or Bohr model, presented by Niels Bohr and Ernest Rutherford in 1913, is a system consisting of a small, dense nucleus surrounded by orbiting electrons—similar to the structure of the Solar System, but with attraction provided by electrostatic forces in place of gravity.
