Answer:
(a) Radius of orbit will be 
(b) Earth gravitational force will be 
(C) Height will be 
Explanation:
We have given
Mass of the earth, 
Mass of the satellite, m = 5600 kg
Radius of earth, 
Time period T = 6200 sec
We know that 
Now
(a) We know that 


Radius of the orbit 
(b)
Force 
(c)
Altitude 
Answer:
y = -3x + 1
Explanation:
Isolate the variable, y. Note the equal sign, what you do to one side, you do to the other. Subtract 3x from both sides of the equation:
3x + y = 1
3x (-3x) + y = 1 (-3x)
y = -3x + 1
y = -3x + 1 is your answer.
~
They are transverse and travel at the speed of light.
Answer:
Explanation:
F = G*m1 * m2 / r^2
G = 6.67408 × 10-11 m3 kg-1 s-2
r = 15 m
F = 4.60 * 10^-6 N
m1 = m2 = m
F = 6.67 * 10^-11 * m^2 / 15^2
4.60 * 10^-6 = 6.67 * 10^-11 * m^2 / 225 Multiply both sides by 225
4.60*10^-6 * 225 = 6.67*10^-11 * m^2
.001035 = 6.67408 × 10-11 * m^2 Divide by 6.67408 × 10-11
0.001035/ 6.67408 × 10-11 = m^2
m^2 = 15507755 Take the square root of both sides
m = sqrt(15507755 )
m = 3938 kg
The answer would be D
Because there are the same amount of elements on each side (3Mg on the left and 3 Mg on the right. Then 2 N on the left and 2 N on the right also)