The original Coulomb force between the charges is:
Fc=(k*Q₁*Q₂)/r², where k is the Coulomb constant and k=9*10⁹ N m² C⁻², Q₁ is the first charge, Q₂ is the second charge and r is the distance between the charges.
The magnitude of the force is independent of the sign of the charge so I can simply say they are both positive.
Q₁ is decreased to Q₁₁=(1/3)*Q₁=Q₁/3 and
Q₂ is decreased to Q₂₂=(1/2)*Q₂=Q₂/2.
New force:
Fc₁=(k*Q₁₁*Q₂₂)r², now we input the decreased values of the charge
Fc₁=(k*{Q₁/3}*{Q₂/2})/r², that is equal to:
Fc₁=(k*(1/3)*(1/2)*Q₁*Q₂)/r²,
Fc₁=(k*(1/6)*Q₁*Q₂)/r²
Fc₁=(1/6)*(k*Q₁*Q₂)/r², and since the original force is: Fc=(k*Q₁*Q₂)/r² we get:
Fc₁=(1/6)*Fc
So the magnitude of the new force Fc₁ with decreased charges is 6 times smaller than the original force Fc.
The number of pulse beats elapsed before the rubber ball hits the ground can be obtained when you carry out the experiment yourself. However, the pulse beat method of timing used by Galileo is not reliable because it varies from time to time.
Galileo was interested in studying how objects fall. His discovery was that all objects had the same acceleration irrespective of their mass. This observation was in direct contrast to Aristotle's assertion that the velocity of objects is proportional to their mass.
However, he used his pulse beats as timer during the experiment. This method is unreliable because the pulse beats of a person changes depending on the person's state of mind. A stop clock could have been a more reliable timer than pulse beats.
Learn more: brainly.com/question/7201885
Answer:
mixtures that appear to be the same throughout are homogenous mixtures
my answer is round. or a circle. if thats not right i can help you if you have multiple choice answers