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2 years ago

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Sharks also swim in waters off the coast of Nova Scotia. When gray seals and harbor seals see sharks nearby, they must swim away

quickly or get eaten by the shark. Since the sharks and seals live in the same waters. could this interaction be called symbiosis? Why or why not? If not, what is this interaction called

1 answer:

Vlada [557]2 years ago

6 0

No. The seals are responding to a stimulus.

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Two rigid tanks of equal size and shape are filled with different gases. The tank on the left contains oxygen, and the tank on t

fredd [130]

Answer:

The number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.

Explanation:

Given:

Molar mass of oxygen, $M_O=32$

Molar mass of hydrogen, $M_H=2$

We know ideal gas law as:

$PV=nRT$

where:

P = pressure of the gas

V = volume of the gas

n= no. of moles of the gas molecules

R = universal gs constant

T = temperature of the gas

∵ $n=\frac{m}{M}$

where:

m = mass of gas in grams

M = molecular mass of the gas

∴Eq. (1) can be written as:

$PV=\frac{m}{M}.RT$

$P=\frac{m}{V}.\frac{RT}{M}$

as: $\frac{m}{V}=\rho\ (\rm density)$

So,

$P=\rho.\frac{RT}{M}$

Now, according to given we have T,P,R same for both the gases.

$P_O=P_H$

$\rho_O.\frac{RT}{M_O}=\rho_H.\frac{RT}{M_H}$

$\Rightarrow \frac{\rho_O}{32}=\frac{\rho_H}{2}$

$\rho_O=16\rho_H$

∴The molecules of oxygen are more densely packed than the molecules of hydrogen in the same volume at the same temperature and pressure. So, <em>the number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.</em>

5 0

2 years ago

A bird is flying east at 5.2 kilometers/hour relative to the air. There's a crosswind blowing at 3.1 kilometers/hour toward the

alexandr402 [8]

Answer:

r=6.05km/hr

z=59.1 degree to the horizontal

Explanation:

A bird is flying east at 5.2 kilometers/hour relative to the air. There's a crosswind blowing at 3.1 kilometers/hour toward the south relative to the ground. What is the bird's velocity relative to the ground? State your answer to one decimal place

can be solved using pythagoras theorem

r^2=o^2+a^2

r^2=5.2^2+3.1^2

r^2=36.65

r=6.1km/hr is te birds velocity relative to the ground

tanz=5.2/3.1

z=tan^-1(5,2/3.1)

z=59.1 degree to the horizontal

7 0

2 years ago

Read 2 more answers

Which of the following statements are true? Positively charged objects attract other positively charged objects. Negatively char

butalik [34]

The statement that is true is that positively charged objects attract negatively charged objects. This is due to a law that states 'like forces attract while unlike forces repel. This same concept applies to magnetism. If you put two similar poles together, for example; if you place two south poles together. You feel a separating force between the two poles. But if you place two opposite poles together they attract each other. Hope i helped. <span />

7 0

2 years ago

Read 2 more answers

What is the resultant force on the human cannonball in the

Svetllana [295]

Answer:

heart

Explanation:

4 0

2 years ago

Meteor Infrasound A meteor that explodes in the atmosphere creates infrasound waves that can travel multiple times around the gl

ladessa [460]

Answer:

The frequency of these waves is $4.27\times10^{-2}\ Hz$

Explanation:

Given that,

Wavelength = 6.6 km

Distance = 8810 km

Time t = 8.67 hr

We need to calculate the velocity of sound

Using formula of velocity

$v = \dfrac{D}{T}$

Where, D = distance

T = time

Put the value into the formula

$v =\dfrac{8810}{8.67}$

$v=1016\ km/hr$

We need to calculate the frequency

Using formula of frequency

$v=n\lambda$

$n=\dfrac{v}{\lambda}$

Put the value into the formula

$n=\dfrac{1016}{6.6}$

$n=153.93\ hr$

$n=\dfrac{153.93}{60\times60}$

$n=0.0427\ Hz$

$n=4.27\times10^{-2}\ Hz$

Hence, The frequency of these waves is $4.27\times10^{-2}\ Hz$

8 0

3 years ago