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sattari [20]
3 years ago
6

Tammy leaves the office, drives 34 km due north, then turns onto a second highway and continues in a direction of 35◦ north of e

ast for 79 km. What is her total displacement from the office? Answer in units of km. \ At what angle is her displacement? (C
Physics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

The total displacement is 102 km 51^o north of east.

Explanation:

We can treat this problem as a trigonometric one, so we need to calculate the total displacement on the north and east.

d_n=34km+79km*sin(35^o)=79km

and

d_e=79*cos(35^o)=65km

The total displacement is given by:

D=\sqrt{(79km)^2+(65km)^2}=102km

with an agle of:

\alpha =arctg(\frac{79km}{65km})=51^o

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When light travels from a medium with higher refractive index to a medium with lower refractive index, there is a critical angle after which all the light is reflected (so, there is no refraction).

The value of this critical angle can be derived by Snell's law, and it is equal to
\theta_C = \arcsin ( \frac{n_2}{n_1} )
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In our problem, n1=1.47 and n2=1.33, so the critical angle is
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