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sattari [20]
3 years ago
6

Tammy leaves the office, drives 34 km due north, then turns onto a second highway and continues in a direction of 35◦ north of e

ast for 79 km. What is her total displacement from the office? Answer in units of km. \ At what angle is her displacement? (C
Physics
1 answer:
Natasha2012 [34]3 years ago
4 0

Answer:

The total displacement is 102 km 51^o north of east.

Explanation:

We can treat this problem as a trigonometric one, so we need to calculate the total displacement on the north and east.

d_n=34km+79km*sin(35^o)=79km

and

d_e=79*cos(35^o)=65km

The total displacement is given by:

D=\sqrt{(79km)^2+(65km)^2}=102km

with an agle of:

\alpha =arctg(\frac{79km}{65km})=51^o

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Which object is not accelerating?
AleksAgata [21]
I would say d because the student isn’t moving, the Ferris wheel is.
8 0
3 years ago
Read 2 more answers
Es
IrinaVladis [17]

Answer:

A leaf is falling from the tree.

Explanation:

If motion is in only one direction(x-direction) then it is know as one directional motion.

If motion is in only two direction (x and y directions) then it is know as two directional motion.

If motion is in only three direction (x , y and z directions) then it is know as three directional motion.

A bird is flying in the air -This is three directional motion.

A leaf is falling from the tree - This is two directional motion.

A train is running on track - This is  one directional motion

A lady is crawling  on the surface of the ball - This is three directional motion.

Therefore the answer is  ---

A leaf is falling from the tree.

3 0
3 years ago
Arrange the following types of photons of electromagnetic radiation in order of decreasing energy: red light, radio, x-rays, γ-r
MrRa [10]

Answer:The correct order is

γ-rays > x-rays> red light > infrared > radio

Explanation:

In the electromagnetic spectrum we have the following electromagnetic radiation Radio waves, infrared radiation, visible light, ultraviolet light, X-ray and gamma rays. Gamma rays have the highest  frequency and radio waves the lowest. From the formula;

E=hf,      where;

E is energy

h is Planck constant

f is frequency

We can see that the energy of these radiation depends on the magnitude of their frequency. Hence Gamma ray with highest frequency will have the highest energy and radio waves the lowest energy. Red light however is found at the lower end of the visible light spectrum . the correct order is;

γ-rays > x-rays> red light > infrared > radio

8 0
3 years ago
A diffraction grating is illuminated simultaneously with red light of wavelength 660 {\rm nm} and light of an unknown wavelength
Tanzania [10]

Answer:

\lambda = 420 nm

Explanation:

As we know that position of maximum on the screen in diffraction pattern is given as

y = (\frac{2N + 1}{2})\frac{\lambda L}{d}

here we know that

position of third maximum due to red color light and position of fifth maximum of unknown wavelength are same

so we have

\frac{7 \lambda_r L}{2d} = \frac{11 \lambda L}{2d}

so we have

\lambda = \frac{7}{11} \lambda_r

\lambda = \frac{7}{11}(660 nm)

\lambda = 420 nm

7 0
4 years ago
A rocket blasts off vertically from rest on the launch pad with an upward acceleration of 2.90 m/s2 . At 20.0s after blastoff, t
Brilliant_brown [7]

Answer:

A) 580m

B) 0 m/s

C) 9.8m/s^2

D) downward

E) 10.87s

F) 106.62 m/s

Explanation:

A) The distance traveled by the rocket is calculated by using the following expression:

y=\frac{1}{2}at^2

a: acceleration of the rocket = 2.90 m/s^2

t: time of the flight = 20.0 s

y=\frac{1}{2}(2.90\frac{m}{s^2})(20.0s)^2=580m

B) In the highest point the rocket has a velocity with magnitude zero v = 0m/s because there the rocket stops.

C) The engines of the rocket suddenly fails in the highest point. There, the acceleration of the rocket is due to the gravitational force, that is 9.8 m/s^2

D) The acceleration points downward

E) The time the rocket takes to return to the ground is given by:

t=\sqrt{\frac{2y}{g}}=\sqrt{\frac{2(580m)}{9.8m/s^2}}=10.87s

10.87 seconds

F) The velocity just before the rocket arrives to the ground is:

v=\sqrt{2gy}=\sqrt{2(9.8m/s ^2)(580m)}=106.62\frac{m}{s}

6 0
3 years ago
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