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Tanzania [10]
3 years ago
15

After their loss to U of A, the ASU sumdevils traveled back to Tempe which is 187

Physics
1 answer:
Dmitry_Shevchenko [17]3 years ago
5 0

The average speed is 20.8 m/s

Explanation:

The average speed for the trip is given by:

v=\frac{d}{t}

where

d is the distance covered

t is the time elapsed

For the trip in this problem, we have:

d = 187 km = 187,000 m is the distance travelled

The initial  time is 10:00 pm while the arriving time is 12:30 am: this means that the time elapsed is 2.5 hours. Converting into seconds,

t = 2.5 h \cdot (60)(60)=9000 s

Therefore, the average speed for the trip is

v=\frac{187,000}{9000}=20.8 m/s

Learn more about average speed:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

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A string attached to an airborne kite is maintained at an angle of 41 degrees with the horizontal. If a total of 152 m of string
satela [25.4K]

Answer:

The  horizontal displacement is  Adj  =  114.71 \ m

Explanation:

From the question we are told that  

    The  angle at which the string is maintained is  \theta  =  41 ^o

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Using the SOHCAHTOA formula

   We have that the hypotenuse(Hyp) is  l  =  152

Hence the  horizontal displacement of the kite  which is the Adjacent(Adj)  can be evaluated as  

     cos \theta  =  \frac{Adj}{Hyp }

substituting values

     cos(41)  =  \frac{Adj}{152}

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3 years ago
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