The relationships to determine the number of calories to change 0.50 kg of 0°C ice to 0°C ice water is 1,080,000 cal.
<h3>How does heating ice that is at C affect it?</h3>
Ice melts and becomes liquid water at 0 degrees Celsius. Once all of the ice has been entirely transformed into liquid water, the temperature of the remaining ice begins to increase once more (in °C), continuing to rise until it reaches 100 °C, where it then stabilizes.
The water turns into steam when it reaches a temperature of 100 °C (D).
Water has a fusion latent heat of fusion of 80 cal/g.
Water has a 1 cal/g-C specific heat.
Water has a 540 cal/g latent heat of vaporization.
In light of this, the total amount of heat needed is 1500 g [(80 cal/g) + (1 cal/g-C)(100 - 0)C + (540 cal/g)] = 1500 g [(720 cal/g)] = 1,080,000 cal.
To learn more about Vaporization refer to:
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<u>Answer</u>
3.44 m/s
<u>Explanation</u>
The motion apply the equations of Newton's law of motion. The ball is acceleration is -9.8 m/s² (acceleration due to gravity. It is negative because the ball is going against gravity, so it is decelerating).
The first equation of Newton's law of motion is;
V = U + at
Where V is the final velocity, U is the initial velocity, a is acceleration and t the time taken.
V = 25 + (-9.8 × 2.2)
= 25 - 21.56
= 3.44 m/s
Answer:
Mesothermal regions have moderate climates. They are not cold enough to sustain a layer of winter snow but are also not remain warm enough to support flowering plants (and, thus, evapotranspiration) all year.
Explanation:
Please give the brainliest.
Answer:
1.4 m/s/s (2.s.f)
Explanation:
The formula for centripetal acceleration is:
, where v is velocity and r is the radius.
In the question we are given the information that the car has a mass of 1300kg, a velocity of 2.5m/s, and a turn radius of 8.5m which are all the values we need. Therefore we can simply substitute in the values to solve the question:
Therefore the centripetal acceleration of the car is 1.4m/s/s. (2.s.f)
Hope this helped!
