please help me with my question I will like and mark as brainliest for the first correct answer due tomorrow morning
1 answer:
You might be interested in
Answer:
F = 0.112 N
Explanation:
To find the magnitude of magnetic force on the wire, you use the following formula:
(1)
L: length of the wire = 200cm = 0.2m
i: current in the wire = 30 A
B: magnitude of the magnetic field = 0.055 T
θ: angle between the directions of L and B = 20°
You replace the values of L, i, B and θ in the equation (1):
hence, the magnetic force on teh wire is 0.112N
Answer with Explanation:
Electric field:It is the force per unit charge experienced by rest charge at any given point.
It is the area around the charge which is placed at rest.It is represented by E.
Mathematical formula:
Magnetic field:It is an area around moving charge in which moving charge particle experienced magnetic force in that area.
Magnetic field is represented by B.
Mathematical formula :
Where B=Magnetic field
q=Charge on particle
v=Velocity of particle
F=Magnetic force exert on particle
Answer:
The positions are 0.0194 m and - 0.0194 m.
Explanation:
Given;
amplitude of the simple harmonic motion, A = 2.0 cm = 0.02 m
speed of simple harmonic motion is given as;
the maximum speed of the simple harmonic motion is given as;
when the speed equal one fourth of its maximum speed
Thus, the positions are 0.0194 m and - 0.0194 m.