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Savatey [412]
3 years ago
12

The chart below describes the molecular motion in solids, liquids, gases, and plasma.

Chemistry
1 answer:
Sidana [21]3 years ago
7 0

Answer:

Liquids

Note: the attachment below shows the properly arranged chart

Explanation:

The order of molecular motion of matter from fastest to slowest is;

Plasma>Gases>Liquids>Solids

Liquids move faster than solids not slower.

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How a convection current can enable a hawk or eagle to soar upward without flapping its wing 
Maurinko [17]
The convection current is one of hot air rising, in this example, and then cooling and returning down. The rising air pushes the eagle up higher into the air. It just has to spread its wings and let the air push it into the air
6 0
2 years ago
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Calculate the number of hydrogen atoms in a 110.0 sample of tetraborane(B4H10) . Be sure your answer has a unit symbol if necess
Contact [7]

Answer:

1.242 \times 10^{25}\text{ atoms H}

Explanation:

You must convert the mass of B₄H₁₀ to moles of B₄H₁₀, then to molecules of B₄H₁₀, and finally to atoms of H.

1. Moles of B₄H₁₀

\text{Moles of B$_{4}$H}_{10} = \text{110.0 g B$_{4}$H}_{10} \times \dfrac{\text{1 mol B$_{4}$H}_{10}}{\text{53.32 g B$_{4}$H}_{10}} = \text{2.063 mol B$_{4}$H}_{10}

2. Molecules of B₄H₁₀

\text{No. of molecules} = \text{2.063 mol B$_{4}$H}_{10} \times \dfrac{6.022 \times 10^{23}\text{ molecules B$_{4}$H}_{10}}{\text{1 mol B$_{4}$H}_{10}}\\\\=1.242 \times 10^{24}\text{ molecules B$_{4}$H}_{10}

3. Atoms of H

\text{Atoms of H} = 1.242 \times 10^{24}\text{ molecules B$_{4}$H}_{10} \times \dfrac{\text{10 atoms H}}{\text{1 molecule B$_{4}$H}_{10}}\\\\= \mathbf{1.242 \times 10^{25}}\textbf{ atoms H}

8 0
3 years ago
An atom's configuration based on its number of electrons ends at 3p3. Another atom has nine more electrons. Starting at 3p, what
77julia77 [94]
<h3><u>Answer;</u></h3>

3p34s23d7

<h3><u>Explanation</u>;</h3>
  • Electrons in an atom are contained in specific energy levels that are different distances from the nucleus.
  • Within each energy level is a volume of space where specific electrons are likely to be located, called orbitals. Orbitals are of different shapes, denoted by a letter (s, p, d, f, g).
  • S-orbital takes a maximum of two electrons, p-orbital take a maximum of six electrons, d-orbital takes a maximum of 10 electrons, and so fourth.
  • The electron filling pattern takes; 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p.........
  • Therefore; in this case after 3p3, we then go to 4s, with 2 electrons, then 3d which takes 7 electrons.

8 0
2 years ago
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Manganese-58 has a half-life of about 3 seconds. If you have a 90.0 gram sample, how
Rus_ich [418]

Answer:

18.018 seconds.

Explanation:

Given that the half life of Manganese, Mn = 3 seconds. The initial sample mass = 90.0 gram, the final sample mass = 1.40 gram.

The general idea to the question is to look for the time it will take to decay from the initial mass that is 90 gram to 1.40 gram.

Therefore, we will be making use of the formula below;

J(t) = J(o) × (1/2)^t/t(hL).

Where t(hL) is the half life, t is the time taken, J(t)= mass after time,t and J(o) is the initial mass. So, let us slot in the values into the equation above.

1.4 = 90 × (1/2)^ t/3.

1.4/90 = (1/2)^t/3.

t/3 = log(0.5) (1.4/90).

+Please note that the 0.5 of the log is at the subscript).

That is the base 0.5 logarithm of (1.4/90) 0.01556 is 6.0060141295.

t = 3 × 6.0060141295.

t = 18.018 seconds.

4 0
3 years ago
What is the mass in grams of 2.8 x 10^19 formula units of beryllium nitrate
makkiz [27]
To convert the formula unit to mass, we need to divide the given formula units by Avogadro's number, 6.022 x 10^23 and we get the mole of beryllium nitrate. To convert to mass, we need to multiply the number of moles with the molecular formula of the compound which is 133.022 g/mol.The answer is 0.006185 g or 6.185 mg. 
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2 years ago
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