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3 years ago

5

In which sample of water do the water particles have more energy: 5 grams of ice cubes at -10 degrees Celsius or 5 grams of liqu

id water at 20 degrees Celsius? How do you know

1 answer:

Ivenika [448]3 years ago

6 0

Higher temperature = higher energy. In water it is a liquid as the particles have more energy so vibrate and are further away from each other.

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Classify each as the following:element, compound, or mixture:

Studentka2010 [4]

1. element
2. compound
3. element
4. compound
5. compound
6. compound

basically, if its on the periodic table, its an element. for example, rock can be made of many things in the periodic table, therefore its a compound. salt, is NaCl, which are two elements put together, therefore its a compound.

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3 years ago

26. For each of the following balanced equations, calculate how many grams of each product would be pro-

Dimas [21]

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3 years ago

Mariana [72]

Answer:

P(O₂) = 287.41 mmHg

P(O₂) = 413.59 mmHg

Explanation:

Given data:

Total pressure = 701 mmHg

Mass of methane = 2.75 g

Mass of oxygen = 3.45 g

Partial pressure of each gas = ?

Solution:

Number of moles of methane:

Number of moles = mass/molar mass

Number of moles = 2.75 g/ 16 g/mol

Number of moles = 0.17 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 3.45 g/ 32 g/mol

Number of moles = 0.12 mol

Total number of moles = 0.12 mol + 0.17 mol = 0.29 mol

Partial pressure of oxygen:

P(O₂) = [ moles of oxygen / total moles ] × total pressure

P(O₂) = [0.12 / 0.29 ] × 701 mmHg

P(O₂) = 0.41 × 701 mmHg

P(O₂) = 287.41 mmHg

Partial pressure of methane:

P(O₂) = [ moles of oxygen / total moles ] × total pressure

P(O₂) = [0.17 / 0.29 ] × 701 mmHg

P(O₂) = 0.59 × 701 mmHg

P(O₂) = 413.59 mmHg

5 0

3 years ago

Calculate the pH of a buffer that is prepared by mixing 25.0 mL of 0.300 M methylamine (CH3NH2) and 0.405 g of methylammonium ch

SVETLANKA909090 [29]

<u>Answer:</u> The pH of the solution is 10.74

<u>Explanation:</u>

<u>For methylammonium chloride:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of methylammonium chloride = 0.405 g

Molar mass of methylammonium chloride = 67.52 g/mol

Putting values in above equation, we get:

$\text{Moles of methylammonium chloride}=\frac{0.405g}{67.52g/mol}=0.00599mol$

<u>For methylamine:</u>

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of methylamine solution = 0.300 M

Volume of solution = 25 mL = 0.025 L

Putting values in above equation, we get:

$0.300M=\frac{\text{Moles of methylamine}}{0.025L}\\\\\text{Moles of methylamine}=(0.300mol/L\times 0.025L)=0.0075mol$

Total volume of the solution = [25 + 500] = 525 mL = 0.525 L (Conversion factor: 1 L = 1000 mL)

To calculate the pOH of basic buffer, we use the equation given by Henderson Hasselbalch:

$pOH=pK_b+\log(\frac{[salt]}{[base]})$

$pOH=pK_b+\log(\frac{[CH_3NH_3^+Cl^-]}{[CH_3NH_2]})$

We are given:

$pK_b$ = negative logarithm of base dissociation constant of methylamine = 3.36

$[CH_3NH_2]=\frac{0.0075}{0.525}$

$[CH_3NH_3^+Cl^-]=\frac{0.00599}{0.525}$

pOH = ?

Putting values in above equation, we get:

$pOH=3.36+\log (\frac{(0.00599/0.525)}{(0.0075/0.525)}\\\\pOH=3.26$

To calculate the pH of the solution, we use the equation:

$pH+pOH=14\\\\pH=14-3.26=10.74$

Hence, the pH of the solution is 10.74

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3 years ago

Solid aluminum carbide reacts with water to produce methane gas and solu

Alex787 [66]

Answer: So, You need to write about Solids Gases and Liquids so do something simple but very smart.....

Explanation:

YOU CAN DO IT!!!

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2 years ago