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kolezko [41]
3 years ago
5

Increase the pressure on the system

Chemistry
1 answer:
Molodets [167]3 years ago
6 0

Answer:

What do you mean????????

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The Texas high plains region does not revive much rain. It is reasonable to predict that this region, compared to other ecoregio
mixas84 [53]

Answer:

Less soil erosion

Explanation:

Due to the low amount of rainfall in this region, it is easier to say that the region compared to other ecoregion will suffer less soil erosion.

Erosion is usually the washing away of the top layer of the soil. Rainfall is one of the most important element that causes erosion. Surface runoff for an extended period of time can remove the topmost layer of the earth on which plant can grow. This starves the soil of its rich nutrients and minerals.

8 0
3 years ago
Helppp ! Please :’)
Over [174]

Answer:

\boxed{\sf \lambda \:  = 1.282 \times    {10}^{ 3} nm}

Explanation:

Suppose an electron makes transition from n initial (ni) to n final (nf) then formula for wavelength is given by,

\frac{1}{ \lambda}  = R_H {Z}^{2}  \big(\frac{1}{{n_f^2}}  - \frac{1}{{n_i^2}} \big)

Where,

  • λ is wavelength of photon
  • Rʜ is rydberg constant, the value of Rʜ is

109690 Cm-¹ in <em>Puri Sharma Pathania</em> standard book of physical chemistry &

109737 Cm-¹ according to <em>Wikipedia</em>

  • Z is the atomic number of atom, for hydrogen Z =1,

& according to given data, ni = 5, nf = 3

Solution:

Let's solve for wavelength,

Substituting all the given data in above formula,

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \big(\frac{1}{{3^2}}  - \frac{1}{{5^2}} \big)

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \big(\frac{1}{{9}}  - \frac{1}{{25}} \big)

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \times   \frac{25 - 9}{25 \times 9}

\frac{1}{ \lambda}  = 109690 \times  {1}^{2}  \times   \frac{16}{225}

\frac{1}{ \lambda}  =   7800.18 \: \: cm ^{ - 1}

\lambda = 1.282 \times  {10}^{ - 4} cm

Now we know that, 1 cm = 10000000 nm,

Converting the wavelength from Cm → Nm

\lambda \:  = 1.282 \times  {10}^{ - 4} \times  {10}^{7}

\lambda \:  = 1.282 \times  {10}^{ - 4 + 7}

\sf \lambda \:  = 1.282 \times    {10}^{ 3} nm

\sf \small Thanks \:  for \:  joining \:  brainly  \: community!

4 0
2 years ago
It requires 2,500 joules to raise a certain amount of water (c = 4.186J/g°C) from 25.0°C to 55.0°C.
maksim [4K]

Answer:

15g

Explanation:

6 0
4 years ago
One example of an ionic compound is<br><br> F2 <br> CO2<br> HBr<br> MgCL2
allochka39001 [22]
MgCl2 because it is the only option in which a metal appears with a nonmetal. In this case, the metal transfers electrons to the nonmental because the metal has a lower ionization energy.
7 0
4 years ago
Read 2 more answers
Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
9966 [12]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

5 0
3 years ago
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