Explanation:
The balanced equation of the reaction is given as;
Mg(OH)2 (s) + 2 HBr (aq) → MgBr2 (aq) + 2 H2O (l)
1. How many grams of MgBr2 will be produced from 18.3 grams of HBr?
From the reaction;
2 mol of HBr produces 1 mol of MgBr2
Converting to masses using;
Mass = Number of moles * Molar mass
Molar mass of HBr = 80.91 g/mol
Molar mass of MgBr2 = 184.113 g/mol
This means;
(2 * 80.91 = 161.82g) of HBr produces (1 * 184.113 = 184.113g) MgBr2
18.3g would produce x
161.82 = 184.113
18.3 = x
x = (184.113 * 18.3 ) / 161.82 = 20.8 g
2. How many moles of H2O will be produced from 18.3 grams of HBr?
Converting the mass to mol;
Number of moles = Mass / Molar mass = 18.3 / 80.91 = 0.226 mol
From the reaction;
2 mol of HBr produces 2 mol of H2O
0.226 mol would produce x
2 =2
0.226 = x
x = 0.226 * 2 / 2 = 0.226 mol
3. How many grams of Mg(OH)2 are needed to completely react with 18.3 grams of HBr?
From the reaction;
2 mol of HBr reacts with 1 mol of Mg(OH)2
18.3g of HBr = 0.226 mol
2 = 1
0.226 = x
x = 0.226 * 1 /2
x = 0.113 mol
Answer:
Oxygen
Explanation:
I'm not completely sure about the explosion part but I know oxygen fuels fire.
Answer:
0.702M
Explanation:
Molarity of a solution, which refers to the molar concentration of that solution can be calculated thus;
Molarity = number of moles (n) ÷ volume (V)
Firstly, we convert 18.5 grams of NaCl to moles using the formula; mole = mass/molar mass
molar mass of NaCl = 23 + 35.5 = 58.5g/mol
mole = 18.5/58.5
mole = 0.32moles
Volume of water (V) = 450mL = 450/1000 = 0.450L
Molarity = n/V
Molarity = 0.32/0.450
Molarity = 0.702M
For the answer to the question above, one of the most important risks to take into account regarding the mining of uranium is the possibility of nuclear decay taking place and contaminating the worker. So I believe the answer is the last one which is <span>the health hazards that are associated with uranium mining</span>
