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exis [7]
3 years ago
8

Select the correct locations on the periodic table.

Chemistry
2 answers:
ale4655 [162]3 years ago
5 0

Answer : The correct location on the periodic table of two elements have similar characteristics is, two elements present in the second column of the left side

Explanation :

The elements have similar characteristics when they are belong to the same family or group this means that when they are placed in the same column of the periodic table.

The elements of similar characteristics have same number of valence electrons.

In the given periodic table of the elements, the two elements present in the second column of the left side have similar characteristics because these two elements belong to the same family or group. While the other elements have different characteristics.

Alexus [3.1K]3 years ago
4 0

Explanation:

It is known that atoms that have same number of valence electrons will show similar chemical properties.

So, when we move from left to right across a period there occurs increase in number of valence electrons of each element. But when we move down a group then number of valence electrons remain the same.

Hence, elements of same group will show similar chemical properties.

Therefore, we can conclude that elements marked as 2 and 3 will have similar chemical properties.

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At what temperature a gas with volume 175 L at 15 oC and 760mmHg will occupy a volume of 198 L at a pressure 640mmHg?
MrRissso [65]

Answer:

To calculate the pressure when temperature and volume has changed, we use the equation given by combined gas law. The equation follows:

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

T

1

P

1

V

1

=

T

2

P

2

V

2

where,

P_1,V_1\text{ and }T_1P

1

,V

1

and T

1

are the initial pressure, volume and temperature of the gas

P_2,V_2\text{ and }T_2P

2

,V

2

and T

2

are the final pressure, volume and temperature of the gas

We are given:

\begin{gathered}P_1=760mmHg\\V_1=175L\\T_1=15^oC=[15+273]K=288K\\P_2=640mmHg\\V_2=198L\\T_2=?K\end{gathered}

P

1

=760mmHg

V

1

=175L

T

1

=15

o

C=[15+273]K=288K

P

2

=640mmHg

V

2

=198L

T

2

=?K

Putting values in above equation, we get:

\begin{gathered}\frac{760mmHg\times 175L}{288K}=\frac{640mmHg\times 198L}{T_2}\\\\T_2=274K\end{gathered}

288K

760mmHg×175L

=

T

2

640mmHg×198L

T

2

=274K

Hence, the temperature when the volume and pressure has changed is 274 K

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