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Alekssandra [29.7K]
3 years ago
10

What is difference between kilowatt and kilowatt hour?

Physics
2 answers:
Sedaia [141]3 years ago
7 0
Kilowatt hour is a measure of ENERGY
Kilowatt is a measure of POWER
Scrat [10]3 years ago
6 0
Those two units can be compared to a 'mile per hour' and a 'mile per hour - hour'.
One is a rate.  The other is a quantity, after maintaining a rate for some time.

-- 'Joule' is a unit of energy.  It's the amount of work (energy) you do
when you push with a force of 1 newton though a distance of 1 meter.
Lifting 10 pound of beans 3 feet off the floor takes about 40.7 joules of energy.

-- 'Watt' is a <u><em>rate</em></u> of using energy . . . 1 joule per second.
If you lift 10 pounds 3 feet off the floor in 1 second, your <em>power</em> is 40.7 watts.

-- 'Watt-second' is the amount of energy used in one second,
at the rate of 1 joule per second . . . 1 joule.

-- 'Watt-hour' is the amount of energy used in one hour,
at the rate of 1 joule per second . . . 3,600 joules.

-- 'Kilowatt' is a bigger <em>rate</em> of using energy . . . 1,000 joules per second.

-- 'Kilowatt - second' is the amount of energy used in one second,
at the rate of 1,000 joules per second . . . 1,000 joules .

-- 'Kilowatt - hour' is the amount of energy used in one hour,
at the rate of 1,000 joules per second . . . 3,600,000 joules .

Depending on where you live, 3,600,000 joules of energy bought
from the electric company costs something between 5¢ and 25¢.


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Which person will most likely hear the loudest sound?
Nataliya [291]

Person standing on A will hear the loudest sound

Explanation:

The intensity of a sound wave (which is proportional to the loudness of the sound) follows an inverse square law, which is:

I\propto \frac{1}{r^2}

where

I is the intensity of the wave

r is the distance from the source of the sound

This equation means that the intensity of the sound wave (and therefore, its loudness) is inversely proportional to the square of the distance  from the source: therefore,

  • As we get closer to the source of sound, the loudness increases
  • As we move away from the source of sound, the loudness decreases

Therefore, the person that will hear the loudest sound is the one standing closer to the source, and therefore person A.

Learn more about sound waves:

brainly.com/question/4899681

#LearnwithBrainly

6 0
3 years ago
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An object dropped from rest from the top of a tall building on planet x falls a distance d(t)18 left parenthesis t right parenth
melamori03 [73]

displacement is given by equation

d = 18t^2

now at t = 5 s the position is

d_1 = 18 *5^2 = 450 m

similarly position at t = 9 s

d_2 = 18*9^2 = 1458 m

so the displacement of object in given interval of time will be

d = 1458 - 450 = 1008 m

time interval

\delta t = 9 - 5 = 4 s

now the average velocity will be given as

v = \frac{\delta x}{\delta t}

v = \frac{1008}{4} = 252 m/s

so its average speed is 252 m/s

4 0
3 years ago
List three ways in which the study of science has made modern life different from that of 100 years ago​
stealth61 [152]
Life Expectancy Was Shorter
Trains were faster to ride
The population explosion was not as on date
8 0
2 years ago
If a chemical is completely consumed in a chemical reaction, what is the substance?
Dima020 [189]
Is a process in which One set of substances, called REACTANTS, is converted to a new set of substances is called PRODUCTS.

--In other words, a chemical reaction is the process by which a chemical change occurs.
5 0
3 years ago
A,b, e are complete. Help on the others would be so appreciated!!
bixtya [17]

Answer:

serie Ceq=0.678 10⁻⁶ F  and the charge Q = 9.49 10⁻⁶ C

Explanation:

Let's calculate all capacity values

a) The equivalent capacitance of series capacitors

    1 / Ceq = 1 / C1 + 1 / C2 + 1 / C3 + 1 / C4 + 1 / C5

    1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 1 / 6.2 + 1 / 6.2

    1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 2 / 6.2

    1 / Ceq = 0.666 + 0.3030 +0.1818 +0.3225

    1 / Ceq = 1,147

    Ceq = 0.678 10⁻⁶ F

b) Let's calculate the total system load

   Dv = Q / Ceq

   Q = DV Ceq

   Q = 14 0.678 10⁻⁶

   Q = 9.49 10⁻⁶ C

In a series system the load is constant in all capacitors, therefore, the load in capacitor 5.5 is Q = 9.49 10⁻⁶ C

c) The potential difference

   ΔV = Q / C5

   ΔV = 9.49 10⁻⁶ / 5.5 10⁻⁶

   ΔV = 1,725 ​​V

d) The energy stores is

    U = ½ C V²

    U = ½ 0.678 10-6 14²

    U = 66.4 10⁻⁶ J

e) Parallel system

   Ceq = C1 + C2 + C3 + C4 + C5

   Ceq = (1.5 +3.3 +5.5 +6.2 +6.2) 10⁻⁶

   Ceq = 22.7 10⁻⁶ F

f) In the parallel system the voltage is maintained

   Q5 = C5 V

   Q5 = 5.5 10⁻⁶ 14

   Q5 = 77 10⁻⁶ C

g) The voltage is constant V5 = 14 V

h) Energy stores

   U = ½ C V²

   U = ½ 22.7 10-6 14²

   U = 2.2 10⁻³ J

8 0
3 years ago
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