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2 years ago

Can you help with this question please

Physics

1 answer:

Iteru [2.4K]2 years ago

7 0

Answer:

First answer to the first question is Two people pulling a rope with the same force in a opposite direction. The other one would be 2.72N

Explanation:

Hope this helps you :)

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If forces acting on an object are unbalanced, which factor may result from an unbalanced force? The net force is negative. There

Oksi-84 [34.3K]

Answer:the Forces cancel out each other

Explanation:the forces cancel out each other

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2 years ago

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-Dominant- [34]

Answer:

And the force of ( Attraction or repulsion) between the poles A and D ( maximum or minimum)

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suppose that a large cargo truck needs to cross a bridge. the truck is 30 m long and 3.2 m wide. the cargo exerts a force nof 54

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2 years ago

Ill give 15 points to the one who helps me with this

alexandr402 [8]

Machenical number one

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3 years ago

Two subway stops are separated by 1210 m. If a subway train accelerates at 1.30 m/s2 from rest through the first half of the dis

solong [7]

Answer:

Part 1) Time of travel equals 61 seconds

Part 2) Maximum speed equals 39.66 m/s.

Explanation:

The final speed of the train when it completes half of it's journey is given by third equation of kinematics as

$v^{2}=u^2+2as$

where

'v' is the final speed

'u' is initial speed

'a' is acceleration of the body

's' is the distance covered

Applying the given values we get

$v^2=0+2\times 1.30\times \frac{1210}{2}\\\\v^{2}=1573\\\\\therefore v=39.66m/s$

Now the time taken to attain the above velocity can be calculated by the first equation of kinematics as

$v=u+at\\\\v=0+1.30\times t\\\\\therefore t=\frac{39.66}{1.30}=30.51seconds$

Since the deceleration is same as acceleration hence the time to stop in the same distance shall be equal to the time taken to accelerate the first half of distance

Thus total time of journey equals $T=2\times 30.51\approx61seconds$

Part b)

the maximum speed is reached at the point when the train ends it's acceleration thus the maximum speed reached by the train equals $39.66m/s$

4 0

3 years ago