Explanation:
You walk 53m to the north, then you turn 60° to your right and walk another 45m. Determine the direction of your displacement vector. Express your answer as an angle relative to east.
Answer:
48.54 m/s
Explanation:
If the rock takes 9 seconds to reach your position after being thrown, it reaches its maximum height in 4.5 seconds.
The height the rock reaches above your position is ...
h = (1/2)gt^2 = (4.9 m/s^2)(4.5 s)^2 = 99.225 m
This height is an additional 21 m above the water, so the maximum height above the water is ...
99.225 m +21.0 m = 120.225 m
The velocity (v) achieved when falling from this distance is found from ...
v^2 = 2gh
v = √(2(9.8)(120.225)) = √2356.41 ≈ 48.543 . . . . m/s
The speed of the rock when it hits the water is about 48.54 m/s.
Answer:
Weight, air drag, normal.
Explanation:
Since the car is only rolling downhill, the forces that will come into play are: it's own weight (the gravitational force the Earth exerts upon the car), the air resistance (the force the air exerts upon the car, since it says it can't be ignored) and finally the normal force (the contact force the ground exerts on the car). There are no other forces sources.
Answer:
The frequency of the wave is 184.75 Hz.
Explanation:
Given;
wavelength of the wind, λ = 2.23 cm = 0.0223 m
speed of the wind wave, v = 4.12 m/s
the frequency of the wave = ?
The frequency of the wave is calculated as;
F = V / λ
Where;
F is the frequency of the wave
Substitute the given values and solve for F
F = (4.12) / (0.0223)
F = 184.75 Hz.
Therefore, the frequency of the wave is 184.75 Hz.
