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SOVA2 [1]
3 years ago
14

Pweese help one more timeeeepweese look at the image below

Physics
2 answers:
4vir4ik [10]3 years ago
7 0

Answer:

increasing; speeding up is my answer

balandron [24]3 years ago
7 0
That answer is B increasing
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A car has a mass of 1.00 × 103 kilograms, and it has an acceleration of 4.5 meters/second2. What is the net force on the car?
aksik [14]

ANSWER


C. F=4.5 \times10^3. newtons


EXPLANATION


According to Newton's second law,



F_{net}=ma, where



m=1.00\times 10^3kg is the mass measured in kilograms.


and


a=4.5ms^{2} is the acceleration in metres per second square.



We substitute these values to obtain,


F=1.00\times10^3 \times 4.5.



We rearrange to get,


F=1.00\times4.5 \times10^3.


We multiply out the first two numbers and leave our answer in standard form to get,



F=4.5 \times10^3 N.



The correct answer is C


3 0
3 years ago
What is the net force on a bag pulled down by gravity with a force of 18 newtons and pulled upward by a rope with a force of 18
VARVARA [1.3K]

Answer:

0 N.

Explanation:

Force: This can be defined as the product of mass and the acceleration of the body. The S.I unit of force is Newton (N).

The expression of net force when both force act in the different direction is given as

F' = W-F ........................ Equation 1

Where F' = Net force on the bag, W = gravitational force on the bag, F = Force acting upward on the bag

Given: W = 18 N, F = 18 N.

Substitute into equation 1

F' = 18-18

F' = 0 N.

Hence the net force = 0 N.

4 0
3 years ago
The gravitational force between two objects (mass1 = 10kg, mass2 = 6kg) is measured when the objects are 12 centimeters apart. I
Yanka [14]
Since the new distance is 3 times the old distance,
the new force is (1/3²) = 1/9th of the old force.

That's kind-of Choice-D, but I really don't like the way choice-D is worded.
"9 times smaller" is really pretty meaningless.  
8 0
3 years ago
Please help! This is due tomorrow and I absolutely need help.
zysi [14]

Answer:

Correct answer:  11. Total distance d = 200m ; 12. Vav = 3.63m/s ;

13. Total displacement Dt = 0m ; 14. V₂(10s-15s) = 0 m/s ;

15. V₃(15s-40s) = 4 m/s ; 16. V₁(0s-10s) = 6 m/s > V₄(40s-55s) = 2.67 m/s

Explanation:

The whole movement can be divided into four stages.

In the first stage the subject moves 60m in a positive direction for 10s,

in the other it is stationary for 5s, in the third it moves 100m in the opposite (negative) direction for 25s and in the fourth in the positive 40m for 15s.

11. Total distance = 60 + 0 + 100 + 40 = 200m

12. The formula for calculating the average speed (velocity) is

Vav = (S₁ + S₂ + S₃ + S₄) / (t₁ + t₂ + t₃ + t₄)

Vav = (60 + 0 + 100 + 40)/ (10 + 5 + 25 + 15) = 200/55 = 3.63 m/s

13. The movement started from the origin and ended at the origin

Total displacement is zero meters.

14. The speed between 10s and 15s is zero, because he did not move.

15. V₃ = S₃/t₃ = 100/25 = 4 m/s

16. V₁ = S₁/t₁ = 60/10 = 6 m/s   and V₄ = S₄/t₄ = 40/15 = 2.67 m/s

V₁ > V₄

God is with you!!!

4 0
3 years ago
How to make a tangram with paper?
sattari [20]
Just follow these simple steps:
Fold a rectangular piece of paper so that a square is formed. ...
Cut the square into two triangles.
Take one triangle and fold it in half. ...
Take the other triangle and crease it in the middle. ...
Fold the trapezoid in half and fold again. ...
Fold the remaining small trapezoid and cut it in two.
3 0
3 years ago
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