Answer:
The answer to your question is Theoretical yield
Explanation:
Theoretical yield is the quantity of a product obtain considering that all the reactants will be converted into products. The theoretical yield considers that the reaction is 100% effective, but this is not true most of the chemical reactions have a yield of 80 % or lower.
1 mol = 6.022 x 10²³ atoms
In order to find how many atoms, dimly multiply the amount of moles you have by 6.022 x 10²³ or Avogadro's number.
So you have 1.75 mol CHC1₃ x (6.022x10²³) = 1.05385 x 10²⁴ atoms of CHCl₃
But now you have to round because of the rules of significant figures so you get 1.05 x 10²⁴ atoms of CHCl₃
Answer : The activation energy for the reaction is, 52.9 kJ/mol
Explanation :
According to the Arrhenius equation,
or,
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7BK_2%7D%7BK_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= initial temperature = 
= final temperature = 
= rate constant at 
= 
= rate constant at 
= 
= activation energy for the reaction = ?
R = gas constant = 8.314 J/mole.K
Now put all the given values in this formula, we get:
![\log (\frac{25.0s^{-1}}{12.5s^{-1}})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{298.0K}-\frac{1}{308.0K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7B25.0s%5E%7B-1%7D%7D%7B12.5s%5E%7B-1%7D%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B298.0K%7D-%5Cfrac%7B1%7D%7B308.0K%7D%5D)
Therefore, the activation energy for the reaction is, 52.9 kJ/mol
It's inertia. Inertia is the force that resists change in motion, like the planets and gravity. Inertia is effected by gravity
Answer:
A and 3
B and 2
C and 1
Explanation:
<em>Ion</em>ic bonding is the transfer of electrons from a cat<em>ion</em> to an an<em>ion</em>.
Covalent bonding is the sharing of electrons between nonmetal atoms.
<em>Metallic</em> bonding is the sea of electrons <em>metal </em>cations.
Hope this helped!
