Answer:
well the reactions are probably wow and amazed
Answer:
The pressure of N₂O₄ in the reaction vessel after the reaction is 290 mmHg
Explanation:
Nitrogen gas reacts with oxygen gas to form dinitrogen tetroxide.
N₂ (g) + 2O₂ (g) → N₂O₄ (g)
Therefore since by Avogadro's law equal volumes of all gases contain equal numbers of molecules, there fore as the gases are within the same vessel, thier partial pressure is equivalent to their concentration
from the reaction, 1 mole of N₂ react with 2 moles of O₂ to produce 1 mole of N₂O₄
Thus
1 mmHg of N₂ react with 2 mmHg of O₂ to produce 1 mmHg of N₂O₄
337 mmHg N₂ ×(1 mmHg of N₂O₄/ 1 mmHg of N₂) = 337 mmHg N₂O₄
580 mmHg O₂ ×(1 mmHg of N₂O₄/ 2 mmHg of O₂) = 290 mmHg N₂O₄
As seen from the above calculation, the limting reactant is oxygen and the partial pressure of N₂O₄ = 290 mmHg
Answer:
2 C6H6 + 15 O2 ( 12 CO2 + 6 H2O
Explanation:
If the patient is given 150 mL/h of IV saline for 1.5 h 1.97 g NaCl she receive.
<h3>What is Molarity ?</h3>
Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar Concentration. The S.I unit of Molarity is molar (M) or mol/L.
It is expressed as:
Molarity (M) =
Molarity × Volume of solution = Number of moles
As we know that
Number of moles =
So,
Molarity × Volume of solution =
Molarity × Volume of solution × Molar Mass = Mass
Volume =
= 225 mL
Mass of NaCl = Molarity × Volume of solution × Molar Mass
= (0.15 mol/L NaCl) × (58.44 g/mol NaCl) × (225 ml × 0.001)
= 1.97 g NaCl
Thus from the above conclusion we can say that If the patient is given 150 mL/h of IV saline for 1.5 h 1.97 g NaCl she receive.
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