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algol [13]
2 years ago
15

Predict the best choice in each of the following. You may wish to review the chapter on electronic structure for relevant exampl

es.
(a) the most metallic of the elements Al, Be, and Ba
(b) the most covalent of the compounds NaCl, CaCl2, and BeCl2
(c) the lowest first ionization energy among the elements Rb, K, and Li
(d) the smallest among Al, Al+, and Al3+
(e) the largest among Cs+, Ba2+, and Xe
Chemistry
1 answer:
alisha [4.7K]2 years ago
6 0

Explanation:

(a)  It is known that both Be and Ba are group 2 elements. And, in metals more easily an element is able to lose valence electrons more will be its metallic character.

Elements of group 2 have more metallic character as compared to elements of group 3 (Al is a group 3 element).

Therefore, out of the given options Ba is larger in size so, it is most metallic in nature.

(b)   A covalent compound is defined as the compound in which combining atoms form a chemical bond due to sharing of electrons.

Whereas a compound in which combining atoms tend to form a chemical bond due to transfer of electrons is known as an ionic compound.

Both NaCl and CaCl_{2} are ionic in nature. On the other hand, in BeCl_{2} size of Be is smaller and it has high charge density due to which it will attract the valence electrons of chlorine atom.

Hence, sharing of atoms occur in BeCl_{2}. Hence,  BeCl_{2} is a covalent compound.

(c)  Ionization energy is defined as the heat or energy necessary to remove an electron from a gaseous atom or ion.

Larger is the size of an atom, less amount of energy will be needed by it to remove a valence electron. Hence, lower will be the value of ionization energy.

Therefore, out of the given options Rb has the lowest first ionization energy.

(d)    Higher is the positive charge on an atom smaller will be its size because a positive charge occurs due to loss of electrons.

As a result, size of an atom becomes small. Therefore, out of the given options Al^{3+} is the smallest.

(e)   When we move from left to right in a periodic table then there will be decrease in size of atom due to the addition of electrons into same shells.

Cs is placed at the bottom right corner and Xe is placed at the bottom left corner of a periodic table.

Hence, size of Cs^{+} is largest as compared to both Ba^{+} and Xe.

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6. If 0.500 mol NaN3 react, what mass in grams of nitrogen will result?
lions [1.4K]

Answer:

21 g of N₂ are produced by the decomposition

Explanation:

The reaction is: 2 NaN3 → 2 Na + 3 N2

2 moles of sodium nitride decompose in order to produce 2 moles of Na and 3 moles of nitrogen gas.

According to stoichiometry, ratio is 2:3. Therefore we say,

2 moles of nitride can produce 3 moles of N₂

Then, 0.5 moles of NaN₃ will produce (0.5 . 3) / 2 = 0.75 moles of N₂

We convert the moles to mass, to find the answer

0.75 mol . 28 g / 1 mol = 21 g

7 0
3 years ago
Tried solving this multiple ways, but keep getting the wrong answer. So, I would appreciate the help. Thank you.​
Aliun [14]

Answer:

I can give you the definition ... That might help cause I honestly don't kno the answer either ;-;

Explanation:

When used as a diacritic mark, the term dot is usually reserved for the interpunct, or to the glyphs 'combining dot above' and 'combining dot below' which may be combined with some letters of the extended Latin alphabets in use in Central European languages and Vietnamese.

Here is an example:

The dot product between a unit vector and itself is also simple to compute. In this case, the angle is zero and cosθ=1. Given that the vectors are all of length one, the dot products are i⋅i=j⋅j=k⋅k=1.

5 0
3 years ago
In the synthesis reaction, the white powder produced is magnesium oxide (mgo, mm = 40.3 g/mol). how many moles of magnesium oxid
gulaghasi [49]
Number of moles = mass of product / molecular mass
=mass of product (MgO) / 40.3

Since the mass of MgO is not given in the question, the correct answer choice cannot be given.  However, proceeding witht eh above formula will enable you to find the correct number of moles given the mass of MgO.
3 0
3 years ago
0.10 M potassium chromate is slowly added to a solution containing 0.20 M AgNO3 and 0.20 M Ba(NO3)2. What is the Ag+ concentrati
erastova [34]

Answer:

[Ag^{+}]=4.2\times 10^{-2}M

Explanation:

Given:

[AgNO3] = 0.20 M

Ba(NO3)2 = 0.20 M

[K2CrO4] = 0.10 M

Ksp of Ag2CrO4 = 1.1 x 10^-12

Ksp of BaCrO4 = 1.1 x 10^-10

BaCrO_4 (s)\leftrightharpoons  Ba^{2+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ba^{2+}][CrO_{4}^{2-}]

1.2\times 10^{-10}=(0.20)[CrO_{4}^{2-}]

[CrO_{4}^{2-}]=\frac{1.2\times 10^{-10}}{(0.20)}= 6.0\times 10^{-10}

Now,

Ag_{2}CrO_4(s) \leftrightharpoons  2Ag^{+}(aq)\;+\;CrO_{4}^{2-}(aq)

Ksp=[Ag^{+}]^{2}[CrO_{4}^{2-}]

1.1\times 10^{-12}=[Ag^{+}]^{2}](6.0\times 10^{-10})

[Ag^{+}]^{2}]=\frac{1.1\times 10^{-12}}{(6.0\times 10^{-10})}= 1.8\times 10^{-3}

[Ag^{+}]=\sqrt{1.8\times 10^{-3}}=4.2\times 10^{-2}M

So, BaCrO4 will start precipitating when [Ag+] is 4.2 x 1.2^-2 M

                       

7 0
3 years ago
A gas has a volume of 340.0 mL at 45.90 oC. What is the new temperature of the gas, in Kelvin, if the volume increased to 550.0
d1i1m1o1n [39]

Answer:

Solution for A gas has a volume of 340.0 mL at 45.90 degree celsius. What is the new temperature of the gas, in kelvin, if the volume increased to 550.0 mL.

Missing: oC. ‎| Must include: oC.

Explanation:

6 0
3 years ago
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