Complete the equation for the dissociation of cdcl2(aq). omit water from the equation because it is understood to be present.
1 answer:
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Answer:
The correct option is;
B) 179 g
Explanation:
The parameters given are;
Mass of H₂ that takes part in the reaction = 2.23 g
Molar mass of hydrogen gas, H₂ = 2.016 g
Number of moles, n, of hydrogen gas H₂ is given by the relation;
Chemical equation for the reaction;
H₂ + Br₂ → 2HBr
Given that one mole of H₂ reacts with one mole of Br₂ to produce two moles of HBr
1.106 mole of H₂ will react with 1.106 mole of Br₂ to produce 2 × 1.106 which is 2.212 moles of HBr
The molar mass, of HBr = 80.91 g/mol
The mass of HBr produced = Molar mass of HBr × Number of moles of HBr
The mass of HBr produced = 80.91 × 2.212 = 178.997 g ≈ 179 grams
Therefore, the correct option is B) 179 g.
Answer: The most likely partial pressures are 98.7MPa for NO₂ and 101.3MPa for N₂O₄
Explanation: To determine the partial pressures of each gas after the increase of pressure, it can be used the equilibrium constant Kp.
For the reaction 2NO₂ ⇄ N₂O₄, the equilibrium constant is:
Kp =
where:
P(N₂O₄) and P(NO₂) are the partial pressure of each gas.
Calculating constant:
Kp =
Kp = 0.0104
After the weights, the total pressure increase to 200 MPa. However, at equilibrium, the constant is the same.
P(N₂O₄) + P(NO₂) = 200
P(N₂O₄) = 200 - P(NO₂)
Kp =
0.0104 =
0.0104 +
- 200 = 0
Resolving the second degree equation:
=
= 98.7
Find partial pressure of N₂O₄:
P(N₂O₄) = 200 - P(NO₂)
P(N₂O₄) = 200 - 98.7
P(N₂O₄) = 101.3
The partial pressures are = 98.7 MPa and P(N₂O₄) = 101.3 MPa