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GarryVolchara [31]
4 years ago
10

What product(s) would be formed when these are the reactants? BaF2 + Cl2

Chemistry
1 answer:
guapka [62]4 years ago
8 0
BaF2 + Cl2 = BaCl2 + F2
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Which of these molecular geometries forms a molecule with a bent shape?
allsm [11]

Answer:

well plus da cuh cause opp homie freak jit.on 390/it = 30

3 0
3 years ago
What is hard water and how does it form?
max2010maxim [7]
Its like regular water, but has 2 hydrogin atom insted of one. hope this helps
7 0
4 years ago
How many mL of 2M stock solution would I use to prepare 0.500 L of 0.1 M NaCl?
nordsb [41]

Answer:

25 mL

Explanation:

Step 1: Given data

  • Concentration of the concentrated solution (C₁): 2 M
  • Volume of the concentrated solution (V₁): ?
  • Concentration of the diluted solution (C₂): 0.1 M
  • Volume of the diluted solution (V₂): 0.500 L

Step 2: Calculate the volume of the concentrated NaCl solution

We will use the dilution rule.

C₁ × V₁ = C₂ × V₂

V₁ = C₂ × V₂ / C₁

V₁ = 0.1 M × 0.500 L / 2 M

V₁ = 0.025 L = 25 mL

4 0
3 years ago
Calculate the pH of the solution:<br> [OH-] = 1x10^-11M<br> a.11.0<br> b.12.0<br> c.2.7<br> d.3.0
Veronika [31]

p [OH-] = -log[OH-]= -log ( 1x10^-11M) = 11

we know that

p[OH-] + p[H+] = 14

so p[H+] = 14- p[OH-] = 14- 11 = 3

pH = 3, answer

6 0
3 years ago
1.24 moles of magnesium arsenate are dissolved in 1.74 kg of solution. Calculate the molality of the solution.
aleksklad [387]

Answer:

Molality of the solution = 0.7294 M

Explanation:

Given:

Number of magnesium arsenate = 1.24 moles

Mass of solution = 1.74 kg

Find:

Molality of the solution

Computation:

Molality of the solution = Mole of solute / Mass of solution = 1.74 kg

Molality of the solution = 1.24 / 1.7

Molality of the solution = 0.7294 M

6 0
3 years ago
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