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harkovskaia [24]
3 years ago
10

I WILL GIVE BRAINLIEST! ANSWER ASAP! If 50 grams of vinegar and 10 grams of baking soda are poured into a container, what will t

he final mass of the products be?​
Chemistry
1 answer:
Cloud [144]3 years ago
3 0

Answer: Wouldn't that just be 60 grams?

Explanation:

50+10=60

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Are these radiation, conduction, or convection?
irakobra [83]
Hey! 1) Convection [Warm water is less dense, so it rises.] 2) Conduction [The metal skewer is heated by the fire, and it is directly touching your hand. The metal skewer transfers heat to your hand through conduction.] 3) Conduction [The rock is directly touching you, so it transfers heat to you through conduction.] 4) Convection [Convection causes weather systems because hot air sinks and cold air sinks] 5) Convection [The hot air rises because it is less dense while the cold air sinks because it is denser.] ~Hope this helped~
3 0
3 years ago
Need help with question 1.) I got something wrong but i don’t know hurry ASAP
lana [24]

Vinegar is an heterogeneous mixture

Explanation:

3 0
3 years ago
Find the density of an object that has a mass of 5 kg and a<br> volume of 50 cm3.
iren2701 [21]
  • Mass=5kg=5000g
  • Volume=50cm^3

\\ \rm\longmapsto Density=\dfrac{Mass}{Volume}

\\ \rm\longmapsto Density=\dfrac{5000}{50}

\\ \rm\longmapsto Density=100g/cm^3

4 0
2 years ago
Dihydrogen monoxide is a(n) ____. A. covalent compound B. molecular formula C. empirical formula D. Ionic compound​
olga_2 [115]

Answer:

D. Ionic compound

Explanation:

Just based on my opinion

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8 0
2 years ago
When 231. mg of a certain molecular compound X are dissolved in 65. g of benzene (CH), the freezing point of the solution is mea
Elan Coil [88]

Answer:

Molar mass X = 18.2 g/mol

Explanation:

Step 1: Data given

Mass of compound X = 231 mg = 0.231 grams

Mass of benzene = 65.0 grams

The freezing point of the solution is measured to be 4.5 °C.

Freezing point of pure benzene = 5.5 °C

The freezing point constant for benzene is 5.12 °C/m

Step 2: Calculate molality

ΔT = i*Kf*m

⇒ΔT = the freezing point depression = 5.5 °C - 4.5 °C = 1.0 °C

⇒i = the Van't hoff factor = 1

⇒Kf = the freezing point depression constant for benzene = 5.12 °C/m

⇒m = the molality = moles X / mass benzene

m = 1.0 / 5.12 °C/m

m = 0.1953 molal

Step 3: Calculate moles X

Moles X = molality * mass benzene

Moles X = 0.1953 molal * 0.065 kg

Moles X = 0.0127 moles

Step 4: Calculate molar mass X

Molar mass X = mass / moles

Molar mass X = 0.231 grams / 0.0127 moles

Molar mass X = 18.2 g/mol

5 0
3 years ago
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