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geniusboy [140]
3 years ago
11

How many molecules of H3PO4 are in 125 g of H3PO4

Chemistry
1 answer:
vredina [299]3 years ago
8 0

Answer:

2.11 * 10^3 molecules of phosphoric acid

Explanation:

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What is the pOH of a<br> 5.6 x 10-5 M solution of cesium<br> hydroxide (CsOH)?
Rudiy27

Answer: 4.25

Explanation: CsOH=Cs+

pOH= -log10

= -log10(5.6*10^-5)

= -log10(5.6*10^-5)=-(-4.25)

=4.25

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Hi! Which of the following decreases kinetic energy of solvent molecules? ( I need this handed in quickly!)
Black_prince [1.1K]

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4 0
3 years ago
Write the balanced molecular, ionic, and net ionic equations for the reaction when a solution of lithium phosphate is mixed with
Kaylis [27]

Answer:

see explaination

Explanation:

Molecular equation;

2Li3PO4(aq) + 3CaCl2(aq) >>>> Ca3(PO4)2(s) + 6LiCl(aq)

Total ionic equation; . Includes all ions ;

6Li^+(aq) + 2PO4^-3(aq) + 3Ca^+2(aq) + 6Cl^-(aq) >>>> Ca3(PO4)2(s) + 6Li^+(aq) + 6Cl^-(aq)

Net ionic equation; remove common ions from total ionic;

2PO4^-3(aq) + 3Ca^+2(aq) >>>> Ca3(PO4)2(s)

6 0
3 years ago
How many moles of Na₂CO₃ required to create 9.54 liters of a 3.4 M solution
GarryVolchara [31]

Answer:

The answer to your question is 32.44 moles

Explanation:

Data

moles of Na₂CO₃ = ?

volume = 9.54 l

concentration = 3.4 M

Formula

Molarity = \frac{number of moles}{volume}

Solve for number of moles

number of moles = Molarity x volume

Substitution

Number of moles = (3.4)( 9.54)

Simplification

Number of moles = 32.44

3 0
3 years ago
Read 2 more answers
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