The melting point of table salt is 801 degrees C. Is this a physical or chemical property?

1 answer:

3 0

This is a physical property. Physical properties involve changes of phase, or state of matter, of which melting is an example. Melting involves a change from a solid state to a liquid state. The internal energy of the solid increases, usually by applying heat, which increases the temperature to the melting point of the substance.

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What happens in this reaction and why? hept-3-yne + Br2 -->

maw [93]

Here we have to explain and predict the product of the reaction between hept-3-yne and bromine (Br₂)

The reaction between hept-3-yne and bromine produces trans-3,4-dibromo-3-heptene.

The reaction between the unsaturated hydrocarbon with halogen remove the unsaturation in the molecule and produces di halo compound. The reaction proceed through the formation of bromonium ion.

In this reaction as the unsaturation present in the middle of the alkyl chain i.e. hept-3-yne. The reaction will stop after the formation of di-halo compound with one double bond as shown in the figure.

The product will be exclusively trans product as the bromine is a bulky group and the formation of bromonium ion (intermediate) will be one side of the unsaturated compound.

6 0

3 years ago

A 12-liter tank contains helium gas pressurized to 160 \rm atm.How many 3-liter balloons could the 12-L helium tank fill? Keep i

Vikentia [17]

Answer:

636 balloons

Explanation:

If we assume that helium gas follows an ideal gas behaviour, we can use the ideal gas law to solve this problem as follows:

We consider two different states, the initial given by the conditions of the problem statement and the final, when the tank reaches atmospheric pressure and it's no longer able to fill balloons: $P_{1}=160 atm\\V_{1}=12 L\\P_{2}=1 atm\\V_{2}= ?$
To find out what would be this volume 2, we use the Boyle's Law: $P_{1}V_{1}=P_{2}V_{2}\\V_{2}=\frac{P_{1}V_{1}}{P_{2}} \\V_{2}=\frac{160 atm \times 12L}{1 atm}\\V_{2}=1920 L$
Now we find the available volume to fill the balloons by substracting both, volume 2 and volume 1: $V_{b}=V_{2}-V_{1}=1920L-12L=1908 L$
Finally, we determine the quantity of ballons by dividing that available volume between the volume of each ballon: $B=\frac{1908L}{3L} =636 balloons$