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Step2247 [10]
3 years ago
6

An object traveling in a straight line accelerates. What will definitely happen due to the acceleration?

Physics
2 answers:
Damm [24]3 years ago
7 0
"Acceleration" means any change in the speed or direction of motion ... speeding up, slowing down, or turning.  So . . .

<span>-- </span><span>The distance traveled in a certain time may increase or decrease.

-- The displacement covered in a certain time may increase or decrease.

-- The speed of the object may increase or decrease.

-- The velocity of the object (speed/direction) will change. 
</span>
Hope this helps..
marshall27 [118]3 years ago
7 0
Well 2 things could happen 1 it could just keep going 2 well basically acceleration does not depend on time so it could lift off
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3.Three resistors of 25.0Ω, 30.0Ω, and 40.0Ω are in a series circuit with a 6.0-volt battery. What is the current in the circuit
AURORKA [14]

Answer:

Current = 0.063 Amperes

Explanation:

Let the three resistors be R1, R2, and R3 respectively.

Given the following data;

R1 = 25.0Ω,

R2 = 30.0Ω

R3 = 40.0Ω

Voltage = 6 Volts

First of all, we would determine the equivalent or total resistance;

Total resistance (in series) = R1 + R2 + R3

Total resistance = 25.0Ω + 30.0Ω + 40.0Ω

Total resistance = 95 Ω

Next, we find the current flowing through the circuit;

Voltage = current * resistance

Substituting into the formula, we have;

6 = current * 95

Current = 6/95

Current = 0.063 Amperes

5 0
3 years ago
What is the term of movement in a particular direction
Art [367]
That is a vector. It is a combination of direction and velocity. (You can think of Vector from Despicable Me to help you remember the term)
:)
7 0
3 years ago
At the bottom of a frictionless ramp, a 2kg mass reaches a speed of 9 m/s, how high is the top of the ramp? *
noname [10]
V=√(2gs)
9=√(2×9.8×s)
s=4.1m
3 0
2 years ago
A meter stick is held vertically with one end on the floor and is then allowed to fall. Find the speed of the other end when it
Ilia_Sergeevich [38]

Below is the attachment of the solutions.

5 0
3 years ago
A basketball player grabbing a rebound jumps 76.0 cm vertically. How much total time (ascent and descent) does the player spend.
MatroZZZ [7]

Answer: Part(a)=0.041 secs, Part(b)=0.041 secs

Explanation: Firstly we assume that only the gravitational acceleration is acting on the basket ball player i.e. there is no air friction

now we know that

a=-9.81 m/s^2  ( negative because it is pulling the player downwards)

we also know that

s=76 cm= 0.76 m ( maximum s)

using kinetic equation

v^2=u^2+2as

where v is final velocity which is zero at max height and u is it initial

hence

u^2=-2(-9.81)*0.76

u=3.8615 m/s\\

now we can find time in the 15 cm ascent

s=ut+0.5at^2

0.15=3.861*t+0.5*9.81t^2\\

using quadratic formula

t=\frac{-3.861+\sqrt{3.86^2-4*0.5*9.81(-0.15)} }{2*0.5*9.81}

t=0.0409 sec

the answer for the part b will be the same

To find the answer for the part b we can find the velocity at 15 cm height similarly using

v^2=u^2+2as

where s=0.76-0.15

as the player has traveled the above distance to reach 15cm to the bottom

v^2=0^2 +2*(9.81)*(0.76-0.15)

v=3.4595

when the player reaches the bottom it has the same velocity with which it started which is 3.861

hence the time required to reach the bottom 15cm is

t=\frac{3.861-3.4595}{9.81}

t=0.0409

8 0
3 years ago
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