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Step2247 [10]
3 years ago
6

An object traveling in a straight line accelerates. What will definitely happen due to the acceleration?

Physics
2 answers:
Damm [24]3 years ago
7 0
"Acceleration" means any change in the speed or direction of motion ... speeding up, slowing down, or turning.  So . . .

<span>-- </span><span>The distance traveled in a certain time may increase or decrease.

-- The displacement covered in a certain time may increase or decrease.

-- The speed of the object may increase or decrease.

-- The velocity of the object (speed/direction) will change. 
</span>
Hope this helps..
marshall27 [118]3 years ago
7 0
Well 2 things could happen 1 it could just keep going 2 well basically acceleration does not depend on time so it could lift off
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What do it mean by the value of gravitational constant is 6.67×10^-11Nm^2/kg^2<br>​
luda_lava [24]

Answer:

gravitational constant value means it was never change in any particular area of the Earth

8 0
2 years ago
A substance with a define shape and volume is a
Vlad1618 [11]
Solid is the answer.
8 0
3 years ago
Starting from rest, a 5.00-kg block slides 2.50 m down a rough 30.0 incline. The coeffi cient of kinetic friction between the bl
UkoKoshka [18]

Answer:

a) W_g =61.25J

b) W_k = -46.25J

c) W_N = 0

d) W_g would be the same.

   W_k would decrease.

   W_N would be the same.

Explanation:

a) On an inclined plane the force of gravity is the sine component of the weight of the block.

F_g = mg\sin(\theta) = 5(9.8)\sin(30^\circ)\\W_g = F_g x = 5(9.8)\sin(30^\circ)2.5 = 61.25J

b) The friction force is equal to the normal force times coefficient of friction.

F_k = -mg\cos(\theta)\mu_k = -5(9.8)cos(30^\circ)0.436 = -18.5 N\\W_k = -F_kx = -46.25J

c) The work done by the normal force is zero, since there is no motion in the direction of the normal force.

d) The relation between the vertical height and the distance on the ramp is

h = x\sin(\theta)

According to this relation, the work done by the gravity wouldn't change, since the force of gravity includes a term of x\sin(\theta).

The work done by the friction force would decrease, because both the cosine term and the distance on the ramp would decline.

The work done by the normal force would still be zero.

5 0
3 years ago
You work at a garden store for the summer, and you lift a 14 kg bag of fertilizer with a force of 227 N.
nika2105 [10]

Answer:

(a) Acceleration of the bag will be a=16.214m/sec^2  

(B) Weight of the bag will be 137.2 N

Explanation:

We have given mass of the bag m = 14 kg

Force with which bag is lifted = 227 N

(A) According to newtons law we force is equal to F = ma , here m is mass and a is acceleration

So 227=14\times a

a=16.214m/sec^2

(b) Acceleration due to gravity g=9.8m/sec^2

We know that weight is given by W = mg , here m is mass and g is acceleration due to gravity

So weight W=mg=14\times 9.8=137.2N

So weight of the bag will be 137.2 N

8 0
3 years ago
Two parallel slits are illuminated by light composed of two wavelengths. One wavelength is λA = 622nm. The other wavelength is λ
Sergio039 [100]

Answer:

\lambda_{B}=414.67 nm

Explanation:

In this question we have given

\lambda_{A}=622nm

we have to find

\lambda_{B}=?

We know that

optical path difference for bright fringe is given as=n\lambda

Here,

n is order of fringe

and optical path difference for dark fringe is given as=(n+.5)\lambda

since the light with wavelength \lambda_{A} produces its third-order bright fringe at the same place where the light with wavelength \lambda_{B} produces its fourth dark fringe  

it means

optical path difference for 3rd order bright fringe= optical path difference for forth order dark fringe

Therefore,

3\lambda_{A}=(4+.5)\lambda_{B}...............(1)

Put value of \lambda_{A} in equation (1)

3 \times 622=(4+.5)\lambda_{B}

1866=4.5\lambda_{B}

\lambda_{B}=414.67 nm

3 0
3 years ago
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