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seropon [69]
3 years ago
14

Suppose a spring compresses by 5cm if you put a 250 gram weight on top of it. How

Physics
1 answer:
Leokris [45]3 years ago
8 0

Answer:

Option D. 0.061 J

Explanation:

We'll begin by converting 5 cm to m. This can be obtained as follow:

100 cm = 1 m

Therefore,

5 cm = 5 cm × 1 m / 100 cm

5 cm = 0.05 m

Next, we shall convert 250 g to Kg. This can be obtained as follow:

1000 g = 1 Kg

Therefore,

250 g = 250 × 1 Kg / 1000

250 g = 0.25 Kg

Next, we shall determine the weight of the object. This can be obtained as follow:

Mass (m) = 0.25 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Weight (W) =?

W = m × g

W = 0.25 × 9.8

W = 2.45 N

Next, we shall determine the spring constant. This can be obtained as follow:

Compression (e) = 0.05 m

Weight = Force (F) = 2.45 N

Spring constant (K) =?

F = Ke

2.45 = K × 0.05

Divide both side by 0.05

K = 2.45 / 0.05

K = 49 N/m

Finally, we shall determine the potential energy contained in the compressed spring. This can be obtained as follow:

Compression (e) = 0.05 m

Spring constant (K) = 49 N/m

Energy (E) =?

E = ½Ke²

E = ½ × 49 × (0.05)²

E = 24.5 × 0.0025

E = 0.061 J

Therefore, the potential energy contained in the compressed spring is 0.061 J

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2 years ago
What is meant by a colored shadow? If "shadow" means
Natasha_Volkova [10]

Explanation:

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First, your definition of a shadow is incorrect. A shadow is an area that receives less light than its surroundings because a specific source of light is blocked by whatever is "casting" the shadow. Your example of being outside reveals this. The sky and everything around you in the environment (unless you are surrounded by pitch black buildings) is sending more than enough light into your shadow, to reveal the pen to your eyes. The sky itself diffuses the sunlight everywhere, and the clouds reflect plenty of light when they are not directly in front of the Sun.

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4 0
2 years ago
A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4
SIZIF [17.4K]

Answer:

The  value is    v = 47 \  m/s

Explanation:

From the question we are told that

   The initial  speed of the roller coaster is u =  13 \  m/s

    The  length of the hill is  l   = 400 \  m

    The  acceleration of the  roller coaster is a=4.0 \ m/s^2

Generally the acceleration is mathematically represented as

      a =  \frac{ v - u}{ t_f -  t_i }

Here  t_i is the initial time which is equal to zero

         v_f is the final velocity which is mathematically represented as

          v_f  =  \frac{d}{ t_f}

So  

     a =  \frac{ \frac{d}{d_f}  - u }{ t_f - t_i}

     4 = \frac{\frac{400}{ t_f}  - 13}{t_f - 0}

      4 =  \frac{400 - 13t_f}{ t_f} *  \frac{1}{t_f}

     4t_f ^2  +13f  + 400 =

Solving this using quadratic formula we obtain

    t_f =  8.5 \ s

     t_f =  -11.8 \ s

Generally  time cannot be negative so

       t_f =  8.5 \ s

Generally the  final velocity is mathematically represented as

         v = \frac{400}{8.5}

         v = 47 \  m/s

       

5 0
3 years ago
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Answer:

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6 0
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jek_recluse [69]

Answer:

F = 0

Explanation:

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bold indicates vectors

let's write this equation in module form

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consequently the magnetic force is zero

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5 0
3 years ago
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