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faltersainse [42]
3 years ago
10

Question 14 of 30

Physics
2 answers:
kiruha [24]3 years ago
8 0

Answer:

B

Explanation:

HACE 2500 AÑOS NO SE CONOCÍAN LAS CARGAS ATÓMICAS.

docker41 [41]3 years ago
6 0

Answer: a.

Explanation: i have done this before .. hope this helps (⌐■_■)

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HELP NOW PLEASE ANSWER THE QUESTION THE PICTURE IS ATTACHED BELOW
Andrej [43]

Answer:

c

Explanation:

................................................

7 0
3 years ago
MODERN PHYSICS
frosja888 [35]

Answer:

D. n=6 to n=2

Explanation:

Given;

energy of emitted photon, E = 3.02 electron volts

The energy levels of a Hydrogen atom is given as;  E = -E₀ /n²

where;

E₀ is the energy level of an electron in ground state =  -13.6 eV

n is the energy level

From the equation above make n, the subject of the formula;

n² = -E₀ / E

n² = 13.6 eV / 3.02 eV

n² = 4.5

n = √4.5

n = 2

When electron moves from higher energy level to a lower energy level it emits photons;

E = E_0(\frac{1}{n_1^2}-\frac{1}{n_2^2} )\\\\\frac{1}{n_1^2}-\frac{1}{n_2^2} = \frac{E}{E_o} \\\\\frac{1}{4} -\frac{1}{n_2^2} = \frac{3.02}{13.6} \\\\\frac{1}{4} -\frac{1}{n_2^2} =0.222\\\\\frac{1}{n_2^2} = 0.25 - 0.22\\\\\frac{1}{n_2^2} = 0.03\\\\n_2^2 = 33.33\\\\n_2 = \sqrt{33.33} = 6

For a photon to be emitted, electron must move from higher energy level to a lower energy level. The higher energy level is 6 while the lower energy level is 2

Therefore,  The electron energy-level transition is from n = 6 to n = 2

3 0
3 years ago
A 2000 Kg car going 20 m/s crashes into a wall. What is the force of the car on the wall? ​
lidiya [134]

Answer:

40,000N

Explanation:

Force = Acceleration × Mass

2000×20=40,000

4 0
3 years ago
A Fleas can jump up a distance as large as 33 cm horizontally in a single leap (they are only 0.3 mm in size!). What is their la
Alex Ar [27]

Answer:

Launch velocity of the fleas = 1.80 m/s

Explanation:

Optimal launch angle is the angle that guarantees the maximum horizontal distance covered.

Optimum launch angle = 45°

The horizontal distance covered by a projectile is given as Range

R = (u² sin 2θ)/g

u = initial velocity of the projectile (flea) = ?

R = range = 33 cm = 0.33 m

θ = 45°

2θ = 2 × 45° = 90°

Sin 90° = 1

g = acceleration due to gravity = 9.8 m/s²

R = (u²/g)

u² = Rg = 0.33 × 9.8 = 3.234

u = 1.80 m/s

Hope this helps!!!

7 0
3 years ago
If the weight of the bowling ball acts down with a force of 200 N, what force would the table need to push up with to keep the b
zavuch27 [327]
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3 0
4 years ago
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