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Korvikt [17]
3 years ago
10

Suppose the force of gravity on the electron was comparable to the electric force created by the deflection plates. how would th

is change the results of your
Physics
1 answer:
Alexandra [31]3 years ago
3 0
"F=Vector Sum Of The Two Forces" Is the answer.
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Answer:

Explanation:

As the dielectric is inserted between the plates of a capacitor, the capacitance becomes K times and the electric field between the plates becomes 1 / K times the original value. Where, K be the dielectric constant.

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3 years ago
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Does Solid surfaces reflect better than liquid surfaces? If why?
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3 years ago
A parallel-plate capacitor has a plate area of 0.2 m^2 and a plate separation of 0.1 mm. If the charge on each plate has a magni
barxatty [35]

Answer:

The potential difference across the plates is 226 V.

Explanation:

Given;

area of the capacitor plate, A = 0.2 m²

separation, d = 0.1 mm = 0.1 x 10⁻³ m

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Charge on the capacitor is given by;

Q = CV

Where;

C is the capacitance of the capacitor, given as;

C = ε₀A / d

Then, the potential difference across the plates is given by;

V = \frac{Q}{C} = \frac{Qd}{\epsilon_o A} = \frac{(4*10^{-6})(0.1*10^{-3})}{(8.85*10^{-12})(0.2)}\\\\V = 226 \ V

Therefore, the potential difference across the plates is 226 V.

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