Both C and D are technically correct. But I’d go with D in this instance.
when sled just start to move the force on the sled will be equal to the static friction
So here we need to find the value of static friction
We know that
m = 30 kg

now we know that normal force on the block is counterbalanced by weight of the block


now in order to find the friction force we can use



so it requires 59 N of force to move the sled
Applying the Newton Second Law of motion that is F=ma
We have F=395.2N (North) and m=259.1Kg
Putting these values in the equation
395.2 = 259.1 x a than
for a = 395.2/259.1
a = 1.525 m/sec 2