A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 4.60 m/s
1 answer:
Answer:
(a).The value of force applied on the car during acceleration F = 383.32 N
(b).The value of impulse on the car I = 340.4 N-sec
Explanation:
Acceleration of the car = 5.18
Mass of the passengers = 74 kg
Total force experienced by the car = mass × acceleration
⇒ F = m × a
Put the values of mass & acceleration in the above formula we get
Force F = 74 × 5.18
⇒ F = 383.32 N
This is the value of force applied on the car during acceleration.
linear Impulse is given by I = F × Δt
Where F = force applied on the car
Δt = time interval upon which the force is applied on the car
⇒ I = 383.32 × 0.888
⇒ I = 340.4 N-sec
This is the value of impulse on the car.
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Answer:
Answer D : about 1067 meters
Explanation:
There are two steps to this problem:
1) First find the time it takes the plane to stop using the equation for the acceleration:
Where Vf is the final velocity of the plane (in our case: zero )
Vi is the initial velocity of the plane (in our case: 80 m/s)
is the acceleration (in our case -3 m/s^2 - notice negative value because the velocity is decreasing)
with units corresponding to seconds given the quantities involved in the calculation.
2) Second knowing the time it took the plane to stop, now use that time in the equation for the distance traveled under accelerated motion:
Where the answer results in units of meters given the quantities used in the calculation.
We round this to 1067 meters
Answer:
0.0613°C
Explanation:
the given parameters are m=15gm=15×10⁻³ V₁=865m/s V₂=534m/s
the bullet moves with different kinetic energies before and after the penetration, therefore
Kinetic energy before - kinetic energy after = 1/2 × m × ( V₁² - V₂²)
= × 15×10⁻³ × (865² - 534²)
= 3.47 × 10⁻³J
this loss in energy is transferred to the water, therefore
change in temperature =
where c = heat capacity of water = 4.19 x 10^3
m = mass of water = 13.5 kg
= {3.47 × 10⁻³} / {13.5 x 4.19 x 10^3 }
=0.0613°C