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Leno4ka [110]
3 years ago
12

A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 4.60 m/s

in 0.888 s. What are the magnitudes of the linear impulse and the average total force experienced by a 74.0 kg passenger in the car during the time the car accelerates
Physics
1 answer:
serg [7]3 years ago
3 0

Answer:

(a).The value of force applied on the car during acceleration F = 383.32 N

(b).The value of impulse on the car  I = 340.4 N-sec

Explanation:

Acceleration of the car  a = \frac{4.6}{0.888} = 5.18 \frac{m}{s^{2} }

Mass of the passengers = 74 kg

Total force experienced by the car = mass  × acceleration

⇒ F = m × a

Put the values of mass & acceleration in the above formula we get

Force F = 74 × 5.18

⇒ F = 383.32 N

This is the value of force applied on the car during acceleration.

linear Impulse is given by I = F × Δt

Where F = force applied on the car

Δt  = time interval upon which the force is applied on the car

⇒ I = 383.32 × 0.888

⇒ I = 340.4 N-sec

This is the value of impulse on the car.

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A man of mass 50kg ascends a flight of stairs 5m high in 5 seconds. If acceleration due to gravity is 10ms-2, the power expended
Setler79 [48]

The power expended is 500 W

Explanation:

First of all, we start by calculating the work done by the man in order to ascend: this is equal to the gravitational potential energy gained by the man, which is

W=mg\Delta h

where

m = 50 kg is the mass of the man

g=10 m/s^2 is the acceleration of gravity

\Delta h = 5 m is the change in height

Substituting,

W=(50)(10)(5)=2500 J

Now we can calculate the power expended, which is given by

P=\frac{W}{t}

where

W = 2500 J is the work done

t = 5 s is the time elapsed

Substituting, we find

P=\frac{2500}{5}=500 W

Learn more about power:

brainly.com/question/7956557

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3 years ago
A weather balloon is filled to a volume of 6000 L while it is on the ground, at a pressure of 1 atm and a temperature of 273 K.
avanturin [10]

Answer : The final volume of the balloon at this temperature and pressure is, 17582.4 L

Solution :

Using combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 1 atm

P_2 = final pressure of gas = 0.3 atm

V_1 = initial volume of gas = 6000 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 273 K

T_2 = final temperature of gas = 240 K

Now put all the given values in the above equation, we get the final pressure of gas.

\frac{1atm\times 6000L}{273K}=\frac{0.3atm\times V_2}{240K}

V_2=17582.4L

Therefore, the final volume of the balloon at this temperature and pressure is, 17582.4 L

4 0
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How could you test the hypothesis that elephants interpreted the ground signal as being farther away than the air signal?
bekas [8.4K]

Answer:

One way to test the hypothesis is to create two waves, one in the air and one on the ground at the same time. One of them for the elephant to get closer and another for the elephants to move away. Observe the reaction of the animal and with this we know which sound came first.

Explanation:

This hypothesis is based on the fact that the speed of sound in air is v = 343 m / s with a small variation with temperature.

The speed of sound in solid soil is an average of the speed of its constituent media, giving values ​​between

 wood      3900 m / s

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 fabrics     1540 m / s

 earth       5000 m / s wave S

 ground    7000 m / s P wave

 

we can see that the speed on solid earth is an order of magnitude greater than in air.

One way to test the hypothesis is to create two waves, one in the air and one on the ground at the same time. One of them for the elephant to get closer and another for the elephants to move away. Observe the reaction of the animal and with this we know which sound came first.

From the initial information, the wave going through the ground should arrive first.

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C) Explain relative velocity with examples.​
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A student starts a food fight by throwing a 0.5 kg burrito at some girl he likes. He throws it kind-of hard so he accelerates it
Elenna [48]

Explanation:

m = mass of burrito thrown by the student = 0.5 kg

a = acceleration of the burrito thrown by the student = 3 m/s²

F = force applied by the student on the burrito = ?

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F = ma

inserting the values

F = (0.5) (3)

F = 1.5 N

hence the net force on the burrito comes out to be 1.5 N

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