Well, you can't use this word for word, but a good answer would be something like:
Pesticides release harmful chemicals into the air, not only making it toxic and unsafe for us, but it also has the potential to kill off insects. This affects the ecosystem as well, as it reduces the available food source for larger animals such as birds, which in turn, affect another species.
71.8 g of iron (III) oxide (Fe₂O₃) were produced from 3 moles of magnesium oxide (MgO).
Explanation:
We have the following chemical reaction:
2 FeCl₃ + 3 MgO → Fe₂O₃ + 3 MgCl₂
We see from the chemical reaction that 3 moles of magnesium oxide (MgO) will produce 1 mole of iron (III) oxide (Fe₂O₃).
number of moles = mass / molar weight
mass = number of moles × molar weight
mass of Fe₂O₃ = 1 × 71.8 = 71.8 g
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number of moles
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Answer:
X = 5
Explanation:
Total mass here is 1.5g. Now after heating we have a mass of 0.957g Cu. This means heating had caused a loss of 1.5 - 0.957 = 0.543g of water.
Now, we will try to convert this into moles. This can be done by dividing the respective masses by the molar masses. While the mass of water is 18g/mol, the molar mass of CuSO4 is 160g/mol.
The division of the respective masses by the molar masses is thus:
CuSO4 = 0.957/160 = 0.006 moles
H2O = 0.543/18 = 0.03 moles
The ratios of the moles is thus: 0.03/0.006 = 5
Hence, the number of molecules of water of crystallization is 5
This means x = 5
The steeper it is the more it moves
Answer:
3.50 × 10²³ Atoms of Se
Explanation:
As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as <em>Avogadro's Number</em>. So in order to calculate the number of particles (atoms) contained by 0.580 moles of Se, we will use following relation,
Moles = Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹
Solving for Number of Atoms,
Number of Atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹
Putting values,
Number of Atoms = 0.580 mol × 6.022 × 10²³ Atoms.mol⁻¹
Number of Atoms = 3.50 × 10²³ Atoms
Hence,
There are 3.50 × 10²³ atoms present in 0.280 moles of Se.
