A graduated cylinder holds 100 mL of water. A lead weight is dropped into the cylinder bringing the new volume up to 450 mL. If
1 answer:
11.43g/mL
Explanation:
Given parameters:
Volume of water in the graduated cylinder = 100mL
Volume of water + lead weight = 450mL
Mass of lead weight = 4000g
Unknown:
Density of the lead weight = ?
Solution:
Density is the mass per unit volume of a body.
Density =
Volume of the lead weight = volume of water displaced
Volume of lead weight = 450 - 100 = 350mL
Density = = 11.43g/mL
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Answer : The mass of the oxygen gas produced in grams and the pressure exerted by the gas against the container walls is, 96 grams and 1.78 atm respectively.
Explanation : Given,
Moles of = 2.0 moles
Molar mass of = 32 g/mole
Now we have to calculate the moles of
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 mole of react to give 3 mole of
So, 2.0 moles of react to give
moles of
Now we have to calculate the mass of
Therefore, the mass of oxygen gas produced is, 96 grams.
Now we have to determine the pressure exerted by the gas against the container walls.
Using ideal gas equation:
where,
P = pressure of oxygen gas = ?
V = volume of oxygen gas
T = temperature of oxygen gas =
R = gas constant = 0.0821 L.atm/mole.K
w = mass of oxygen gas
= density of oxygen gas = 1.429 g/L
M = molar mass of oxygen gas = 32 g/mole
Now put all the given values in the ideal gas equation, we get:
Thus, the pressure exerted by the gas against the container walls is, 1.78 atm.
Answer:
Explanation:
We already know that the mass number of an atom is the sum of the number of protons and the number of neutrons.
So, the mass number of this isotope is;
Number of protons = 7
Number of neutrons = 8
Mass number = 7 + 8 = 15
Hence, the isotope is;